Question

[Pham Trong Bach]

Tìm x $\in \mathbb{Z}$,biết:

$\begin{array}{l}a)\frac{5}{3}+\frac{-14}{3}<x<\frac{8}{5}+\frac{4}{10};\\ \\ b)\frac{5}{21}+\frac{-3}{7}<\frac{x}{21}<\frac{-2}{7}+\frac{8}{21};\end{array}$

$\begin{array}{l}c)\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\le x\le \frac{15}{4}+\frac{18}{8};\\ \\ d)\frac{11}{3}+\frac{-19}{6}+\frac{-15}{2}\le x\le \frac{19}{12}+\frac{-5}{4}+\frac{-10}{3}\end{array}$

Answer 1

[Cao Minh Tâm]

a) – 3 < x < 2 => x ∈ {-2;-1;0;1}

b) − 4 21 < x 21 < 2 21 => x ∈ {-3;-2;-1;0;1}

c) 1 ≤  x ≤ 6 => x ∈ {-3;-2;-1;0;1}

d) -7 ≤  x ≤ -3 => x ∈ {-3;-2;-1;0;1}