3 2/5 - 2 x X = 3/5
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1 - 2/7 = 7/7 - 2/7 = 5/7
15/42 - 2/7 = 15/42 - 12/47 = 3/47
6/5 x 3 = 18/5
7/3 x 2/5 = 14/15
`1-2/7=7/7-1/7=6/7`
`15/42-2/7=15/42-12/42=3/42=1/14`
`6/5xx3=(6xx3)/5=18/5`
`7/3xx2/5=(7xx2)/(3xx5)=14/15`
\(\dfrac{4}{5}\times\dfrac{5}{8}=\dfrac{20}{40}=\dfrac{1}{2}\)
\(\dfrac{7}{15}+\dfrac{4}{5}=\dfrac{7}{15}+\dfrac{12}{15}=\dfrac{19}{15}\)
\(\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)
\(\dfrac{1}{2}\div\dfrac{2}{5}=\dfrac{1}{2}\times\dfrac{5}{2}=\dfrac{5}{4}\)
\(\dfrac{x-3}{3}=4-\dfrac{1-2x}{5}\)
=>5(x-3)=60-3(1-2x)
=>5x-15=60-3+6x
=>5x-15=6x+57
=>6x+57=5x-15
hay x=-72(nhận)
e) 1/3+1/3:x=1
1/3:x=1-1/3
1/3:x=2/3
x=1/3:2/3
x=1/2
f) x:3/4+1/4=-2/3
x:3/4=-2/3-1/4
x:3/4=-11/12
x=-11/12.3/4
x=-11/16
g) x:(1/2+1/3)=6/5
x:5/6=6/5
x=6/5.5/6
x=1
\(a,\Rightarrow2x^2-18x-2x^2=0\\ \Rightarrow-18x=0\Rightarrow x=0\\ b,\Rightarrow2x^2-5x-12+x^2-7x+10=3x^2-17x+20\\ \Rightarrow5x=22\Rightarrow x=\dfrac{22}{5}\)
\(5.x+x=39-3^{11}:3\)
=>\(x\left(5+1\right)=39-3^{10}\)
=>\(x.6=39-3^{10}\)
=>\(x=\frac{39-3^{10}}{6}=-9835\)
`-5/(2x)=-5`
`=> -5=2x.(-5)`
`=> 2x.(-5)=-5`
`=>2x=-5:(-5)`
`=>2x=1`
`=>x=1:2`
`=>x=1/2`
- 5/2x = - 5
- 5/2x = -5x/2
=>-5x/2=-5
=>-5(x-2)/2=0
=>-5(x+2)=0
=>x+2=0
=>x=2
`@` `\text {Ans}`
`\downarrow`
\(\left(x-\dfrac{1}{5}\right)^2+1=3,5\div7\%\)
`=> (x-1/5)^2 + 1 = 3,5 \div 0,07`
`=> (x-1/5)^2 +1=50`
`=> (x-1/5)^2 = 49`
`=> (x-1/5)^2 = (+-7)^2`
`=>`\(\left[{}\begin{matrix}x-\dfrac{1}{5}=7\\x-\dfrac{1}{5}=-7\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=7+\dfrac{1}{5}\\x=-7+\dfrac{1}{5}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{36}{5}\\x=-\dfrac{34}{5}\end{matrix}\right.\)
Vậy, `x={36/5; -34/5}.`
TL :
\(3\frac{2}{5}\)x 2 x X = \(\frac{3}{5}\)
\(\frac{17}{5}\)x 2 x X = \(\frac{3}{5}\)
\(\frac{34}{5}\)x X = \(\frac{3}{5}\)
X = \(\frac{34}{5}\): \(\frac{3}{5}\)
X = \(\frac{34}{3}\)