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NB
1
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10 tháng 6 2021
1.2 với \(x\ge0,x\in Z\)
A=\(\dfrac{2\sqrt{x}+7}{\sqrt{x}+2}=2+\dfrac{3}{\sqrt{x}+2}\in Z< =>\sqrt{x}+2\inƯ\left(3\right)=\left(\pm1;\pm3\right)\)
*\(\sqrt{x}+2=1=>\sqrt{x}=-1\)(vô lí)
*\(\sqrt{x}+2=-1=>\sqrt{x}=-3\)(vô lí
*\(\sqrt{x}+2=3=>x=1\)(TM)
*\(\sqrt{x}+2=-3=\sqrt{x}=-5\)(vô lí)
vậy x=1 thì A\(\in Z\)
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S
3
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6 tháng 11 2021
Do you l.i.k.e English? - Yes, i do
@Bảo
#Cafe
MN
1
DT
2
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LO
0
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\(d)\)\(1^{2021}+\left[3^8\div3^6+2^2.\left(5-3\right)^3\right]-2021^0\)
\(=\)\(1+\left[3^2+4.2^3\right]-1\)
\(=\)\(1+\left[9+4.8\right]-1\)
\(=\)\(1+\left[9+32\right]-1\)
\(=\)\(1+41-1\)
\(=\)\(42-1\)
\(=\)\(41\)