5x2 + 8 = 53
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Đặt
Vì lim x → 2 f ( x ) - 20 x - 2 = 10 nên f( x) -20 =0 hay f( x) = 20 nên P =5
Khi đó
Suy ra
T= lim x → 2 f ( x ) - 20 x - 2 . lim x → 2 6 ( x - 3 ) ( P 2 + 5 P + 25 ) = 10 . 6 5 . 75 = 4 25
Chọn B.
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\(5x^2-3x-8=0\\ =5x^2+5x-8x-8\\ =5x\left(x+1\right)-8\left(x-1\right)\\ =\left(5x-8\right)\left(x+1\right)\)
\(\Leftrightarrow5x^2+5x-8x-8=0\)
\(\Leftrightarrow5x\left(x+1\right)-8\left(x+1\right)=0\)
\(\Leftrightarrow\left(5x-8\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}5x-8=0\\x+1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{8}{5}\\x=-1\end{matrix}\right.\)
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\(2\times3=6\)
\(8-4=4\)
\(4\times10=40\)
\(5\times1=5\)
\(2\times9=18\)
\(5\times2=10\)
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1: Sửa đề: 3x-5
\(=\dfrac{-x^2\left(3x-5\right)-3\left(3x-5\right)}{3x-5}=-x^2-3\)
2: \(=\dfrac{5x^4-5x^3+14x^3-14x^2+12x^2-12x+8x-8}{x-1}\)
=5x^2+14x^2+12x+8
3: \(=\dfrac{5x^3+10x^2+4x^2+8x+4x+8}{x+2}=5x^2+4x+4\)
4: \(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}=x^2+1-2x\)
5: \(=\dfrac{x^2\left(5-3x\right)+3\left(5-3x\right)}{5-3x}=x^2+3\)
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Chọn D
B = lim x → 2 x 4 − 5 x 2 + 4 x 3 − 8 = lim x → 2 ( x 2 − 1 ) ( x 2 − 4 ) x 3 − 2 3
= lim x → 2 ( x 2 − 1 ) ( x − 2 ) ( x + 2 ) ( x − 2 ) ( x 2 + 2 x + 4 )
= lim x → 2 ( x 2 − 1 ) ( x + 2 ) x 2 + 2 x + 4 = ( 2 2 − 1 ) . ( 2 + 2 ) 2 2 + 2.2 + 4 = 1