23/5 ..... 43/10
20097/10 ......... 20101/10
37/7.........37/7
K
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17 tháng 4 2020
d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37
=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37
=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37
=43/37.1+31/37=43/37.1+31/37
=2=2
E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12
=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12
=−5/24.1+7/12=−5/24.1+7/12
=3/8=3/8
a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7
=3/7−−11/14−2=3/7−−11/14−2
=3/7+11/14−2=3/7+11/14−2
=−11/14=−11/14
b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14
=4/5−3/7=4/5−3/7
=13/35
17 tháng 4 2020
d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37
=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37
=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37
=43/37.1+31/37=43/37.1+31/37
=2=2
E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12
=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12
=−5/24.1+7/12=−5/24.1+7/12
=3/8=3/8
a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7
=3/7−−11/14−2=3/7−−11/14−2
=3/7+11/14−2=3/7+11/14−2
=−11/14=−11/14
b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14
=4/5−3/7=4/5−3/7
=13/35
AV
30 tháng 7
Bước 1: Gom nhóm và chuyển đổi mẫu số
Ta viết lại biểu thức như sau:
A = 7 / (31 × 19) + 5 / (43 × 19) + 3 / (43 × 23) + 11 / (57 × 23) + 19 / (57 × 38)
Bước 2: Biến đổi thành tổng các sai phân
A = 2 × [ 7 / (31 × 38) + 5 / (38 × 43) + 3 / (43 × 46) + 11 / (46 × 57) + 19 / (57 × 76) ]
Bước 3: Áp dụng công thức sai phân
• 7 / (31 × 38) = (1/31 - 1/38)
• 5 / (38 × 43) = (1/38 - 1/43)
• 3 / (43 × 46) = (1/43 - 1/46)
• 11 / (46 × 57) = (1/46 - 1/57)
• 19 / (57 × 76) = (1/57 - 1/76)
Cộng lại:
A = 2 × [ ( (1/31 - 1/38)) + ( (1/38 - 1/43)) + ( (1/43 - 1/46)) + ( (1/46 - 1/57)) + (((1/57 - 1/76)) ]
Rút gọn biểu thức:
A = 2 × (1/31 - 1/76) = 2 × (45 / (31 × 76)) = 90 / 2356 = 45 / 1178
Kết luận:
A = 45 / 1178
S
10 tháng 6 2017
Ta có: \(A=\frac{4}{7.31}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}\)
\(=\frac{20}{35.31}+\frac{30}{35.41}+\frac{45}{50.41}+\frac{35}{50.57}\)
\(=5\left(\frac{4}{31.35}+\frac{6}{35.41}+\frac{9}{41.50}+\frac{7}{50.57}\right)\)
\(=5\left(\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}\right)\)
\(=5\left(\frac{1}{31}-\frac{1}{57}\right)\)
\(B=\frac{7}{19.31}+\frac{5}{19.43}+\frac{3}{23.43}+\frac{11}{23.57}\)
\(=\frac{14}{38.31}+\frac{10}{38.43}+\frac{6}{46.43}+\frac{22}{46.57}\)
\(=2\left(\frac{7}{31.38}+\frac{5}{38.43}+\frac{3}{43.46}+\frac{11}{46.57}\right)\)
\(=2\left(\frac{1}{31}-\frac{1}{38}+\frac{1}{38}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}+\frac{1}{46}-\frac{1}{57}\right)\)
\(=2\left(\frac{1}{31}-\frac{1}{57}\right)\)
\(\Rightarrow\frac{A}{B}=\frac{5\left(\frac{1}{31}-\frac{1}{57}\right)}{2\left(\frac{1}{31}-\frac{1}{57}\right)}=\frac{5}{2}\)
NT
1
AV
30 tháng 7
Ta có: \(A = \frac{4}{7.31} + \frac{6}{7.41} + \frac{9}{10.41} + \frac{7}{10.57}\)
\(= \frac{20}{35.31} + \frac{30}{35.41} + \frac{45}{50.41} + \frac{35}{50.57}\)
\(= 5 \left(\right. \frac{4}{31.35} + \frac{6}{35.41} + \frac{9}{41.50} + \frac{7}{50.57} \left.\right)\)
\(= 5 \left(\right. \frac{1}{31} - \frac{1}{35} + \frac{1}{35} - \frac{1}{41} + \frac{1}{41} - \frac{1}{50} + \frac{1}{50} - \frac{1}{57} \left.\right)\)
\(= 5 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)\)
\(B = \frac{7}{19.31} + \frac{5}{19.43} + \frac{3}{23.43} + \frac{11}{23.57}\)
\(= \frac{14}{38.31} + \frac{10}{38.43} + \frac{6}{46.43} + \frac{22}{46.57}\)
\(= 2 \left(\right. \frac{7}{31.38} + \frac{5}{38.43} + \frac{3}{43.46} + \frac{11}{46.57} \left.\right)\)
\(= 2 \left(\right. \frac{1}{31} - \frac{1}{38} + \frac{1}{38} - \frac{1}{43} + \frac{1}{43} - \frac{1}{46} + \frac{1}{46} - \frac{1}{57} \left.\right)\)
\(= 2 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)\)
\(\Rightarrow \frac{A}{B} = \frac{5 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)}{2 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)} = \frac{5}{2}\)
a) >
b) <
c) =
hỏi vui à ^^
\(\frac{23}{5}>\frac{43}{10}\)
\(\frac{20097}{10}< \frac{20101}{10}\)
\(\frac{37}{7}=\frac{37}{7}\)