7^x+2 + 7^x-1 = 343
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( 3/7 ) 5 x ( 7/3 ) - 1 x ( 5/3 )6 : ( 343/652) - 2
= ( 3/7 x 7/3 ) + 5 - 1 x ( 5/3 : 343/652 ) - 2
= 1 + 5 - 1 x 2 - 1715/1956
= 6 - 2 - 1715/1956
=4 - 1715/1956
= 6109/1715
\(7.7^{x+1}=343\)
\(\Rightarrow7.7^{x+1}=7^3\)
\(\Rightarrow7^{x+1}=7^3:7\)
\(\Rightarrow7^{x+1}=7^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=2-1=1\)
Bai 1
75:73-343:7
=49-49=0
Bai 2
a. 3x:32=243
=> 3x-2=243
=> x-2=5
=> x=7(bạn viết sai đề câu này phải là 243)
b. x=-1;0;1
c. 2x.64=26
=> 2x.26=26
=> 2x=1
=> x=0
\(7^{\frac{1}{2}x-5}=343\)
\(7^{\frac{1}{2}x-5}=7^3\)
\(\frac{1}{2}x-5=3\)
\(\frac{1}{2}x=3+5\)
\(\frac{1}{2}x=8\)
\(x=8:\frac{1}{2}\)
\(x=16\)
\(7^{\frac{1}{2}x-5}=343\)
=>\(7^{\frac{1}{2}x-5}=7^3\)
=> \(\frac{1}{2}x-5=3\)
=> \(x=16\)
a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)
=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)
=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)
b) \(3x^2-2=72\)=> 3x2 = 74 => x2 = 74/3 => x không thỏa mãn
c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)
=> \(\left(19x+50\right):14=9\)
=> \(19x+50=126\)
=> \(19x=76\)
=> x = 4
d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)
=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)
=> \(x\left(2+4+8+16+32\right)=343\)
=> x . 62 = 343
=> x = 343/62
a) \(\left(\frac{1}{2}\right)^x=\frac{1}{32}\)
\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^5\)
=> x = 5
b) \(\left(\frac{5}{7}\right)^x=\frac{125}{343}\)
\(\left(\frac{5}{7}\right)^x=\left(\frac{5}{7}\right)^3\)
=> x = 3
a) \(\dfrac{49}{81}=\dfrac{7^x}{9^x}\)(sửa đề)
\(\Leftrightarrow\left(\dfrac{7}{9}\right)^2=\left(\dfrac{7}{9}\right)^x\)\(\Rightarrow x=2\)
b) \(\dfrac{-64}{343}=\left(-\dfrac{4^x}{7^x}\right)\)(sửa đề)
\(\Leftrightarrow\left(-\dfrac{4}{7}\right)^3=\left(-\dfrac{4}{7}\right)^x\) \(\Rightarrow x=3\)
c) \(\dfrac{9}{144}=\dfrac{3^x}{12^x}\)(sửa đề)
\(\Leftrightarrow\left(\dfrac{3}{12}\right)^2=\left(\dfrac{3}{12}\right)^x\Rightarrow x=2\)
d) \(-\dfrac{1}{32}=\left(-\dfrac{1^x}{2^x}\right)\)(sửa đề)
\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^5=\left(-\dfrac{1}{2}\right)^x\Rightarrow x=5\)
Mong bạn xem lại đề bài.