B=(1^3+2^3+3^3+...+100^3).(2.21-3.14
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23.19 - 23.14 + 12020
= 23.(19 - 14) + 1
= 8.5 + 1
= 41
102 - [60: (56: 54 - 3.5)]
= 100 - [60: (52 - 15)]
= 100 - [60: (25 - 15)]
= 100 - [60 : 10]
= 100 - 6
= 94
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(\dfrac{-3}{25}\cdot\dfrac{4}{17}\cdot\dfrac{5}{-3}\cdot\dfrac{17}{2}=\dfrac{4}{17}\cdot\dfrac{17}{2}\cdot\dfrac{3}{25}\cdot\dfrac{5}{3}=2\cdot\dfrac{1}{5}=\dfrac{2}{5}\)
b: \(=-\dfrac{8}{15}\cdot\dfrac{13}{16}\cdot\dfrac{30}{13}=\dfrac{-8}{15}\cdot\dfrac{15}{8}=-1\)
c: \(=\dfrac{3}{11}\left(\dfrac{2}{9}\cdot\dfrac{-8}{33}+\dfrac{7}{9}\right)=\dfrac{3}{11}\cdot\dfrac{215}{297}=\dfrac{2015}{1089}\)
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Bài 1:
a: Ta có: 8,5<3,5x<15
mà x là số nguyên
nên \(3,5x\in\left\{10,5;14\right\}\)
hay \(x\in\left\{3;4\right\}\)
b: Ta có: \(\left(3-\dfrac{1}{3}x\right):2+1.5=3\)
=>(3-1/3x):2=1,5
=>3-1/3x=3
=>x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
a,\(5.2^2\)\(-18:3^2\)
\(=5.4-18:9\)
\(=20-2\)
\(=18\)
b, \(\text{17.85+15.17-120}\)
\(=17.\left(85+15\right)\)\(-120\)
= \(17.100-120\)
\(=1700-120\)
\(=1580\)
c, \(2^3\)\(.17-2^3\)\(.14\)
= \(2^3\)\(.\left(17-14\right)\)
\(=8.3\)
\(=24\)
Hok tốt !
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\dfrac{3^9.49^3}{9^2.21^4}=\dfrac{3^9.7^6}{3^4.3^4.7^4}=\dfrac{3^9.7^6}{3^8.7^4}=3.7^2=147\)