Question

[em cần]

em cần câu trả lời ạ

Answer 1

[Yen Nhi]

Bài 1: 

\(x^3+2x^2y+xy^2=x.\left(x^2+2xy+y^2\right)=x.\left(x+y\right)^2\)

\(4-x^2-2xy-y^2=4-\left(x^2+2xy+y^2\right)=2^2-\left(x+y\right)^2=\left(2-x-y\right).\left(2+x+y\right)\)

\(x^2+2xy+y^2-xz-yz=\left(x+y\right)^2-\left(xz+yz\right)=\left(x+y\right)^2-z.\left(x+y\right)=\left(x+y\right).\left(x+y-z\right)\)

Bài 2: 

\(\left(3x^2-2x^2y\right):x^2-\left(2xy^2+x^2y\right):\left(\frac{1}{3}xy\right)\)

\(=3x^2:x^2-2x^2y:x^2-2xy^2:\left(\frac{1}{3}xy\right)+x^2y:\left(\frac{1}{3}xy\right)\)

\(=3-2y-6y-3x\)

\(=3-8y-3x\)

\(5x^3:x-\left(2x^2\right)+x^4:\left(2x^2\right)=5x^2-\left(2x^2\right)+\frac{1}{2}x^2=\frac{7}{2}x^2\)