Tìm x biết:
\(\frac{x-2}{4}=\frac{x+3}{5}\)
Nhớ ghi cách giải!
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Những câu hỏi liên quan
6 tháng 3 2016
Ta có:
\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)=\left(-4\right)+1+1+1+1\)
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)
\(\Rightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)
Mà \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\ne0\)
\(\Rightarrow x+329=0\)
\(\Rightarrow x=-329\)
25 tháng 8 2019
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0.\)
\(1+\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}-4+\frac{x+349}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
\(\Rightarrow x+329=0\)
\(\Rightarrow x=-329\)
Study well
25 tháng 8 2019
\(\Rightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Rightarrow\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Mà \(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)
Nên \(x+329=0\Rightarrow x=-329\)
Vậy \(x=-329\)
Chúc bạn học tốt !!!
31 tháng 3 2017
\(\frac{3}{5}.x-x=\frac{-4}{15}\)
<=>\(x.\left(\frac{3}{5}-1\right)=\frac{-4}{15}\)
<=>\(\frac{-2}{5}.x=\frac{-4}{15}\)
<=>\(x=\frac{-4}{15}:\frac{-2}{5}\)
<=>\(x=\frac{2}{3}\)
vậy \(x=\frac{2}{3}\)
VN
31 tháng 3 2017
Ta có:\(\frac{3}{5}.x-x=-\frac{4}{15}\)
\(\left(\frac{3}{5}-1\right).x=-\frac{4}{15}\)
\(\left(\frac{3}{5}-\frac{5}{5}\right).x=-\frac{4}{15}\)
\(\left(-\frac{2}{5}\right).x=-\frac{4}{15}\)
\(x=-\frac{4}{15}:\left(-\frac{2}{5}\right)\)
\(x=-\frac{4}{15}.\left(-\frac{5}{2}\right)\)
\(x=\frac{\left(-4\right).\left(-5\right)}{15.2}\)
\(x=\frac{20}{30}=\frac{2}{3}\)
14 tháng 6 2017
a) \(\left(56\times27+56\times35\right)\div62=56\times\left(27+35\right)\div62=56\times62\div62=56\)
b) \(\frac{0,18\times1230+0,9\times4567\times2+3\times5310\times6}{1+4+7+10+....+52+55-514}\)
\(=\frac{0,18\times1230+\left(0,9\times2\right)\times4567+\left(3\times6\right)\times5310}{1+4+5+.....+52+55-514}\)
\(=\frac{0,18\times1230+0,18\times4567+0,18\times5310}{1+4+7+...+52+55-514}\)
\(=\frac{0,18\times\left(1230+4567+5310\right)}{\left(55+1\right)\times55\div2-514}\)
\(=\frac{0,18\times11107}{971}=\frac{1999,26}{971}\)
LV
23 tháng 3 2018
mình ra cũng giống bạn Forever _ Alone nhé!!!Chẳng qua mình không biết viết phân số
16 tháng 7 2018
Bài 1:
a) Cách 1: ta có: \(\frac{x}{y}=\frac{3}{5}\Rightarrow\frac{x}{3}=\frac{y}{5}\)
ADTCDTSBN
có: \(\frac{x}{3}=\frac{y}{5}=\frac{x-y}{3-5}=\frac{-6}{-2}=3\)
=> x/3 = 3 => x = 9
y/5 = 3 => y = 15
KL:....
Cách 2:
ta có: \(\frac{x}{y}=\frac{3}{5}\Rightarrow\frac{x}{3}=\frac{y}{5}=k\Rightarrow\hept{\begin{cases}x=3k\\y=5k\end{cases}}\)
mà x -y = -6 => 3k - 5k = -6 => -2k = 6 => k = 3
=> x = 3k =>...
...
b) ta có: \(\frac{x}{2}=\frac{y}{3}=\frac{z}{5}=\frac{2y}{6}\)
ADTCDTSBN
có: \(\frac{x}{2}=\frac{2y}{6}=\frac{z}{5}=\frac{x+2y+z}{2+6+5}=\frac{26}{13}=2\)
=> x/2 = 2 => x = 4
y/3 = 2 => y = 6
z/5 = 2 => z = 10
KL:...
cách 2 bn cx lm như cách kia nha
S
16 tháng 7 2018
a,C1: \(\frac{x}{y}=\frac{3}{5}\Rightarrow\frac{x}{3}=\frac{y}{5}=\frac{x-y}{3-5}=\frac{-6}{-2}=3\)
=>x=9,y=15
C2: Đặt x/3=y/5=k => x=3k,y=5k
Ta có: x - y = 3k - 5k = -2k = -6 =>k=3
=>x=9,y=15
b, tương tự a
2/
C1: \(\frac{3x-5}{4}=\frac{x-2}{3}\Rightarrow3\left(3x-5\right)=4\left(x-2\right)\Rightarrow9x-15=4x-8\Rightarrow5x=7\Rightarrow x=\frac{7}{5}\)
C2: \(\frac{3x-5}{4}=\frac{x-2}{3}\Rightarrow3x-5=\frac{x-2}{3}\cdot4\Rightarrow3x-5=\frac{4x-8}{3}\Rightarrow9x-15=4x-8\Rightarrow5x=7\Rightarrow x=\frac{7}{5}\)
S
25 tháng 8 2019
\(\frac{x+2}{327}+\frac{x+3}{326}+....+\frac{x+349}{5}=\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+329}{5}+4=\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\frac{x+329}{5}=\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+....+\frac{1}{324}+\frac{1}{5}\right)=0\Rightarrow x+329=0\Leftrightarrow x=-329\)
VM
25 tháng 8 2019
Bạn tham khảo tại đây nhé: Câu hỏi của trần như.
Chúc bạn học tốt!
19 tháng 6 2017
Ta có : \(\frac{x+6}{2010}+\frac{x+5}{2009}=\frac{x+4}{2008}+\frac{x+3}{2007}\)
\(\Leftrightarrow\frac{x+6}{2010}-1+\frac{x+5}{2009}-1=\frac{x+4}{2008}-1+\frac{x+3}{2007}-1\)
\(\Leftrightarrow\frac{x-2004}{2010}+\frac{x-2004}{2009}=\frac{x-2004}{2008}+\frac{x-2004}{2007}\)
\(\Leftrightarrow\frac{x-2004}{2010}+\frac{x-2004}{2009}-\frac{x-2004}{2008}-\frac{x-2004}{2007}=0\)
\(\Leftrightarrow\left(x-2004\right)\left(\frac{1}{2010}+\frac{1}{2009}-\frac{1}{2008}-\frac{1}{2007}\right)=0\)
Mà : \(\frac{1}{2010}+\frac{1}{2009}-\frac{1}{2008}-\frac{1}{2007}\ne0\)
Nên : x - 2004 = 0
=> x = 2004
11 tháng 4 2020
Câu b
Ta có :x + 3 /1.3 +3/3.5 + 3/5.7+...+3/13.15=2 1/5
X + 2/3.(1-1/3+1/3-1/5+1/5-1/7+...+1/13-1/15)1=11/5
X+2/3.(1-1/15)=11/5
X+ 2/3.14/15=11/5
X + 28/45=11/5
X = 11/5 -28/45
X=71/45
11 tháng 4 2020
Câu a gợi ý
1/2-1/3/1/6=0
1/2- 1/3 - 1/6 ) x (1/2 + 2/3 + 3/4 +4/5 + .......+ 2019 /2020 ) =0
3/4:x=9/10
X = 3/4:9/10
X = 5/6
=> 5 ( x -2) = 4( x+3)
=> 5x -10 = 4x +12
=>5x -4x = 12 +10
=> x =22