thuc hien phep tinh
a) 10.72 _ 10.5+10.32
b)15+(_2)_|_7|+8
c) (3^5 .3^3);3^4
d)1+2+3...+199+200
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15^3+5.15^2-5^3 / 18^3+6.18^2-6^3
=3375+5.225-125 /5832+6.324-216
=3375+1125-125 /5832+1944-216
=4500-125 /7826-216
=4375 /7610
=875 /1522
mk ko bt viết phần nên viết phần bằng dấu gạch / nhé.mk cx ko bt đúng hay sai đâu nhé
\(\frac{4}{5}+\frac{-7}{15}.1,25\)
\(=\frac{4}{5}+\frac{-7}{12}\)
\(=\frac{13}{60}\)
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a, 516 x 2,15 = 1109,4
b, 2,1655 : 5 = 0,4331
c, \(\frac{15}{4}\)x \(\frac{8}{3}\)x \(\frac{16}{25}\)x \(\frac{1}{5}\)
= 10 x \(\frac{16}{25}x\frac{1}{5}\)
= \(\frac{32}{5}x\frac{1}{5}\)
= \(\frac{32}{25}\)
d, \(\frac{3}{7}:\frac{5}{4}x\frac{3}{5}\)
= \(\frac{3}{7}x\frac{4}{5}x\frac{3}{5}\)
= \(\frac{12}{35}x\frac{3}{5}\)
= \(\frac{36}{175}\)
Tách hai dấu ngoặc thành hai vế A và B
Ta có :
A=5.415.99-4.320.89=5.230.318-22.227.320
=229.318(2.5-32)=229.318
B=5.29.619-7.229.276=5.29.219.319-7.229.318
=228.318(5.3-7.2)=228.318
=>A:B=229.318:228:318=2
a,3/7 +1/2-[-3]/70
=13/14 -[-3]/70
=65/70 -[-3]/70
=34/35
b,3/5+-1/25 -35/100
=14/25 - 35/100
=56 /100 -35/100
= 21/100
c ,5/12 -3/-16+3/4
=29/48 +3/4
= 29/48 +36/48
=65/48
d, 5/15 +4/-12 +1/7 -1/-6
= 1/3 +1/-3 +1/7-1/-6
=0+1/7-1/-6
= 13/42
A.\(\dfrac{3}{7}+\dfrac{1}{2}+\dfrac{\left(-3\right)}{70}\)
=\([\dfrac{30}{70}+\dfrac{\left(-3\right)}{70}]\)+\(\dfrac{1}{2}\)
= \(\dfrac{27}{70}+\dfrac{35}{70}\)
=\(\dfrac{62}{70}=\dfrac{31}{35}\)
B.\(\dfrac{3}{5}+\dfrac{-1}{25}-\dfrac{35}{100}\)
=\(\dfrac{60}{100}+\dfrac{-4}{100}-\dfrac{35}{100}\)
=\(\dfrac{60+\left(-4\right)-35}{100}\)
=\(\dfrac{21}{100}\)
C.\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}\)
=\(\left(\dfrac{5}{12}+\dfrac{9}{12}\right)-\dfrac{-3}{16}\)
=\(\dfrac{7}{6}-\dfrac{-3}{16}\)
=\(\dfrac{56}{48}-\dfrac{-9}{48}\)=\(\dfrac{65}{48}\)
D.\(\dfrac{5}{15}+\dfrac{4}{-12}+\dfrac{1}{7}-\dfrac{1}{-6}\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+(\dfrac{-2}{6}-\dfrac{-1}{6})\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{-1}{6}\)
=\((\dfrac{1}{3}+\dfrac{-1}{6})+\dfrac{1}{7}\)
=\(\dfrac{1}{6}+\dfrac{1}{7}\)=\(\dfrac{13}{42}\)
\(\left(3^{15}+3^{16}+3^{17}\right):\left(3^{11}+3^{12}+3^{13}\right)=3^4.\left(3^{11}+3^{12}+3^{13}\right):\left(3^{11}+3^{12}+3^{13}\right)=3^4=81\)
khong thuc hien phep tinh hay cm rang A chia het cho B biet rang
A=(x+1)(x+3)(x+5)(x+7)+15 va B = x+6
\(A=\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15\)
\(A=\left[\left(x+1\right)\left(x+7\right)\right]\left[\left(x+3\right)\left(x+5\right)\right]+15\)
\(A=\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15\)
Đặt \(a=x^2+8x+11\)
\(\Rightarrow A=\left(a-4\right)\left(a+4\right)+15\)
\(\Leftrightarrow A=a^2-16+15\)
\(\Leftrightarrow A=a^2-1\)
Thay a vào A ( :v ) ta có :
\(A=\left(x^2+8x+11\right)^2-1\)
\(A=\left(x^2+8x+11+1\right)\left(x^2+8x+11-1\right)\)
\(A=\left(x^2+8x+12\right)\left(x^2+8x+10\right)\)
\(A=\left(x^2+2x+6x+12\right)\left(x^2+8x+10\right)\)
\(A=\left[x\left(x+2\right)+6\left(x+2\right)\right]\left(x^2+8x+10\right)\)
\(A=\left(x+6\right)\left(x+2\right)\left(x^2+8x+10\right)⋮x+6\left(đpcm\right)\)
\(\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{5}{12}\\ =\dfrac{3}{12}-\dfrac{4}{12}+\dfrac{5}{12}\\ =\dfrac{3-4+5}{12}\\ =\dfrac{4}{12}\\ =\dfrac{1}{3}\)