3/4*7 + 3/7*10 + 3/10*13 +...+3/73*76
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a, A = (\(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\)) - (\(\dfrac{79}{67}-\dfrac{28}{41}\))
= \(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)
= \(\dfrac{1}{3}+\left(\dfrac{12}{67}-\dfrac{79}{67}\right)+\left(\dfrac{13}{41}+\dfrac{28}{41}\right)\)
= \(\dfrac{1}{3}-1+1\)
= \(\dfrac{1}{3}\)
@Mai Tran
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1.\) \(\dfrac{7}{36}-\dfrac{8}{-9}+\dfrac{-2}{3}=\dfrac{7}{36}+\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{7+32-24}{36}=\dfrac{5}{12}.\)
\(2.\) \(\dfrac{-1}{2}+\dfrac{3}{7}-\dfrac{1}{9}+\dfrac{-7}{18}+\dfrac{4}{7}=\dfrac{-9-2-7}{18}+\dfrac{4+3}{7}=\dfrac{-18}{18}+\dfrac{7}{7}=-1+1=0.\)
\(3.\) \(-\dfrac{10}{3}+\dfrac{13}{10}-\dfrac{1}{6}+\dfrac{1}{10}=\dfrac{13+1}{10}+\dfrac{-20-1}{6}=\dfrac{14}{10}+\dfrac{-21}{6}=\dfrac{7}{5}-\dfrac{7}{2}=-\dfrac{21}{10}.\)
\(4.\) \(\dfrac{10}{17}-\dfrac{5}{13}-\left(-\dfrac{7}{17}\right)-\dfrac{8}{13}+\dfrac{11}{25}=\dfrac{10+7}{17}+\dfrac{-5-8}{13}+\dfrac{11}{25}=\dfrac{17}{17}-\dfrac{13}{13}+\dfrac{11}{25}=\dfrac{11}{25}.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1: \(=\dfrac{7}{36}+\dfrac{32}{36}+\dfrac{-24}{36}=\dfrac{15}{36}=\dfrac{5}{12}\)
2: \(=\left(-\dfrac{1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right)+\dfrac{3}{7}+\dfrac{4}{7}\)
\(=\dfrac{-9-2-7}{18}+1=-1+1=0\)
3: \(=\left(-\dfrac{10}{3}-\dfrac{1}{6}\right)+\dfrac{14}{10}\)
\(=-\dfrac{21}{6}+\dfrac{14}{10}=\dfrac{-7}{2}+\dfrac{14}{10}=\dfrac{-35+14}{10}=-\dfrac{21}{10}\)
4: \(=\left(\dfrac{10}{17}+\dfrac{7}{17}\right)-\left(\dfrac{5}{13}+\dfrac{8}{13}\right)+\dfrac{11}{25}=\dfrac{11}{25}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/
6 = 1*2*3
24 = 2*3*4
.......
Số thứ 100: 100*101*102
TỔng dãy trên là A thì bằng:
A = 1*2*3 + 2*3*4 + ..... + 100*101*102
4A = 1*2*3*4 + 2*3*4*4 + .... + 100*101*102*4
4A = [1*2*3*4 - 0*1*2*3]+ [2*3*4*5 - 1*2*3*4]+ ...+[100*101*102*103 - 99*100*101*102]
4A = 0*1*2*3 + [1*2*3*4-1*2*3*4]+[2*3*4*5-2*3*4*5]+..........+[99*100*101*101-99*100*101*102] + 100*101*102*103
4A = 100*101*102*103
A = 25*101*102*103 = 26527650
2/
\(A=\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+...+\frac{3}{73\cdot76}=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{73}-\frac{1}{76}\)
\(A=\frac{1}{4}-\frac{1}{76}=\frac{9}{38}\)
P/s: Vì tử bằng khoẳng cách dưới mẫu nên ta có thể rút gọn nhanh như vậy
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).\left(1-\frac{1}{5}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}\)
\(=\frac{1}{5}\)
b) \(\left(1-\frac{3}{4}\right).\left(1-\frac{3}{7}\right).\left(1-\frac{3}{10}\right)........\left(1-\frac{3}{97}\right).\left(1-\frac{3}{100}\right)\)
\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.......\frac{94}{97}.\frac{97}{100}\)
\(=\frac{1}{100}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
6/4x7 + 6/7x10 + 6/10x13+..........+6/73x76
=1/3x(3/4x7+3/7x10+.......+6/73x76)
= (1/4-1/7+1/7-1/10+.......+1/73-1/76)x3
= (1/4-1/76)
=9/38x3
=27/38
![](https://rs.olm.vn/images/avt/0.png?1311)
Số số hạng là : ( 79 - 1 ) : 3 + 1 = 27 số hạng
Tổng là : ( 79 + 1 ) . 27 : 2 = 1080
Đ/s: 1080
Đặt \(A=\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+...+\frac{3}{73\cdot76}\)
\(A=\frac{1}{4}-\frac{1}{7}+...+\frac{1}{73}-\frac{1}{76}\)
\(A=\frac{1}{4}-\frac{1}{76}=\frac{9}{38}\)
Thanks nha