35+25+27+13
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1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)
\(=2155-174-2155-68+174\)
=-68
2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)
\(=-25\cdot\left(72-21+49\right)\)
\(=-25\cdot100=-2500\)
a)126.(-43)+26.43=43(-126+26)=43(-100)=-4300
b)(-135)(-45)-35.45=-45(-135+35)=-45(-100)=4500
c)113(-27)+27.13=27(-113+13)=27(-100)=-2700
d)125(-35)-(-25).35=-35(125-25)=-35.100=-3500
\(a)126.\left(-43\right)+26.43\)
\(=\left(-126\right).43+26.43\)
\(=43\left(-126+26\right)\)
\(=43.\left(-100\right)\)
\(=-4300\)
\(b)\left(-135\right).\left(-45\right)-35.45\)
\(=135.45-35.45\)
\(=45\left(135-35\right)\)
\(=45.100\)
\(=4500\)
\(c)113.\left(-27\right)+27.13\)
\(=\left(-113\right).27+27.13\)
\(=27\left(-113+13\right)\)
\(=27.\left(-100\right)\)
\(=-2700\)
\(d)125.\left(-35\right)-\left(-25\right).35\)
\(=\left(-125\right).35-\left(-25\right).35\)
\(=35\left(-125+25\right)\)
\(=35.\left(-100\right)\)
\(=-3500\)
1) 42/35 - [ 33/14 . 21/22 - ( 54/25 : 27/25 - 7/10 )]
= 42/35 - ( 9/4-13/10)
=42/35-19/20
=1/4
2) a) 5/21 . x/34 = 35/102
x/34=35/102 : 5/21
x/34=49/34
=> x=34
Vậy x=34
b) 15/x . 21/13 = 45/91
15/x=45/91 : 21/13
15/x=15/49
=> x=49
Vậy x=49
a) `123 - 27 + 27 + 13 - 123`
`= (123 - 123) + (27 - 27) + 13`
`= 0 + 0 + 13`
`= 13`
`---`
b) `175 + 25 + 13 + 15 - 175 - 25`
`= (175-175)+(25-25)+25+13`
`=0+0+25+13`
`=28`
`---`
c) \(53\times39+47\times39+53\times21+47\times21\)
\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)
\(=\left(100\times39\right)+\left(100\times21\right)\)
\(=3900+2100\)
`=6000`
`---`
d) \(49\times35+49\times16-49\times61\)
`=` \(49\times\left(35+16-61\right)\)
`=` \(49\times\left(-10\right)\)
`=-490`
a) \(\dfrac{3}{35}+\dfrac{7}{20}+\dfrac{32}{35}+\dfrac{13}{20}\)
Áp dụng tính chất giao hoán, kết hợp của phép cộng, ta được:
\(\left(\dfrac{3}{35}+\dfrac{32}{35}\right)+\left(\dfrac{7}{20}+\dfrac{13}{20}\right)\)
\(=1+1\)
\(=2\)
b) \(\dfrac{18\cdot15\cdot56}{42\cdot27\cdot25}=\dfrac{2\cdot3\cdot3\cdot5\cdot3\cdot4\cdot2\cdot7}{2\cdot3\cdot2\cdot2\cdot3\cdot9\cdot5\cdot5}\)
\(=\dfrac{2\cdot2\cdot3\cdot3\cdot3\cdot4\cdot5\cdot7}{2\cdot2\cdot2\cdot3\cdot3\cdot5\cdot5\cdot9}=\dfrac{3\cdot2\cdot2\cdot7}{2\cdot5\cdot9}=\dfrac{42}{45}\)
1) 2155-(174+2155)+(-68+174-7)-1911-(1234-1911)
=2155-174-2155+(-68)+174-7-1911-1234+1911
=(2155-2155)+(174-174)+(1911-1911)-(68+7+1234)
= 0 + 0 + 0 - 1309
= -1309
35+25+27=67
35+25+27+13= 100