9^24.27^13/3^65.81^5 tim x
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a) 3x = 32 . 9
3x = 32 . 32
3x = 34
=> x = 4
b) ( 21 + x ) : 9 = 95 : 94
(21 + x ) : 9 = 9
21 + x = 9 . 9
21 + x = 81
x = 81 - 21
x = 60
c) 5x + 1 - 13 = 613
5x = 613 + 13 - 1
5x = 625
5x = 54
=> x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
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a) 17.13+17.42-17.35
=17.(13+42-35)
=17.20=340
b) [25.(18-42)-10]:4+6
=(25.2-10):4+6
=40:4+6=16
c) 36:32+23.22-32.3
=34+25-33
=81+32-27=86
d) B=3.42-22.3
=3.(16-4)
=3.12=36
e)20220+3.[52.10-(23-13)2]
=1+3.(250-100)
=1+450=451
g) 27.77+24.27-27
=27.(77+24-1)
=27.100=2700
h) 5.23+79:77-12020
=40+72-1
=89-1=88
i) 120:{54[50:2+(32-2.4)]}
=120:[54(25+1)]
=120:1404=10/117
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\(\frac{5}{7}+\frac{3}{4}=\frac{41}{28}\)\(Đ\)
\(3+\frac{2}{5}=1\)\(S\)
\(\frac{11}{9}-\frac{5}{6}=\frac{7}{18}\)\(Đ\)
\(4-\frac{3}{7}=\frac{25}{7}\)\(Đ\)
\(x+\frac{4}{11}=\frac{3}{5}\).
\(x=\frac{3}{5}-\frac{4}{11}\)
\(x=\frac{13}{55}\)
Vậy ta chọn câu C
dung hay sai
5/7 + 3/4 = 41/28 .....Đ...
3 + 2/5 = 1....S....
11/9 - 5/6 = 7/18....Đ...
4 - 3/7 = 25/7.....
tim x
x + 4/11 =3/5
Đáp án : C .13/55
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có
1 = 0 + 1;
5 = 2 + 3;
9 = 4 + 5;
....
x = a + ( a + 1 )
=> 1 + 5 + 9 + 13 + 17 + ... + x = 501
= 1 + 2 + 3 + 4 + 5 + 6 + 7 + ... + a + ( a + 1 ) = 506
Hay [ ( a - 1 ) - 1 ] x ( a - 1) 2 [ ( a - 1 ) - 1 ] x ( a - 1 ) 2 = 506
=> ( a + 1 ) x ( a + 2 ) = 506
=> a = 21
Do đó x = 21 + 21 + 1 = 43
Ta có
1 = 0 + 1;
5 = 2 + 3;
9 = 4 + 5;
....
x = a + ( a + 1 )
=> 1 + 5 + 9 + 13 + 17 + ... + x = 501
= 1 + 2 + 3 + 4 + 5 + 6 + 7 + ... + a + ( a + 1 ) = 506
Hay [ ( a - 1 ) - 1 ] x ( a - 1) 2 [ ( a - 1 ) - 1 ] x ( a - 1 ) 2 = 506
=> ( a + 1 ) x ( a + 2 ) = 506
=> a = 21
Do đó x = 21 + 21 + 1 = 43
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta co :
x+1:4+1=501501
x+1:4 = 501501-1
x+1:4 =501500
x+1 = 501500:4
x+1 = 125375
x = 125375 -1
x =125374
Vay x=125735
**** nhe
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1+5+9+...+x=501501\)
\(\Leftrightarrow\frac{\left(1+x\right).\left[\left(x-1\right)\div4+1\right]}{2}=501501\)
\(\Leftrightarrow\left(1+x\right).\left[\left(x-1\right)\div4+1\right]=501501.2\)
\(\Leftrightarrow\left(1+x\right).\left[\frac{x-1}{4}+1\right]=1003002\)
\(\Leftrightarrow\frac{x-1}{4}\left(1+x\right)+x+1=1003002\)
\(\Leftrightarrow\frac{x-1}{4}+\frac{x-1}{4}x+x=1003001\)
\(\Leftrightarrow\frac{x-1+x\left(x-1\right)+4x}{4}=1003001\)
Tự giải tiếp