x – 2 là ước của 17
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TV
1
AH
Akai Haruma
Giáo viên
27 tháng 12 2021
Lời giải:
$a=5^4.13^2.17^1$.
Số ước nguyên dương của $a$ là: $(4+1)(2+1)(1+1)=30$
Do đó số ước (cả âm cả dương) của $a$ là: $30.2=60$
LD
0
31 tháng 10 2021
\(\Leftrightarrow1-x\in\left\{1;17\right\}\\ \Leftrightarrow x\in\left\{0;-16\right\}\)
NN
31 tháng 10 2021
Ư(17 ) = { 1;17 }
Vì : x - 1 = 1 => x = 2
x - 1 = 17 => x = 18
Vậy x ∈ { 2; 18 }
IL
5
2
7 tháng 2 2020
nếu đây là bài tìm x thì cách làm ý a như sau :
a. | 24 - x | - 30 = -17
| 24 - x | = -17 + \((\) -30 \()\)
| 24 - x | = -47
\(\Rightarrow\) 24 - x = -47 hoặc 24 - x = 47
x = 24 - \((\)- 47 \()\) x = 24 - 47
x = 71 x = -23
\(\Rightarrow\) x = 71 ; x = -23
YN
7 tháng 2 2020
a, | 24 - x | - 30 = -17
=> | 24 - x | = -17 + 30
=> | 24 - x | = 13
\(\Rightarrow\orbr{\begin{cases}24-x=13\\24-x=-13\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=24-13=11\\x=24+13=37\end{cases}}\)
Vậy \(x\in\left\{11;37\right\}\)
b Cho hỏi bội con là gì vậy ạ ( mình ko nhớ là mình từng học về bội con )
c) Ta có x là ước của 12
và - 6 <x < 6
\(\Rightarrow x\in\left\{-4;-3;-2;-1;1;2;3;4\right\}\)
Vậy...
Câu c hơi thiếu thuyết phục
@@ Học tốt @@
# Chiyuki Fujito
9 tháng 11 2016
nguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
AH
Akai Haruma
Giáo viên
7 tháng 10 2023
Lời gải:
a. $7x+3\vdots x$
$\Rightarrow 3\vdots x$ (do $7x$ đã chia hết cho $x$)
$\Rightarrow x\in\left\{1; 3\right\}$ (do $x$ là số tự nhiên)
b.
$17-4x\vdots x$
$\Rightarrow 17\vdots x$ (do $4x$ đã chia hết cho $x$)
$\Rightarrow x\in\left\{1; 17\right\}$
N
2
7 tháng 4 2020
*) 2x-5=-x-17
<=> 2x-5+x+17=0
<=> 3x+12=0
<=> 3x=-12
<=> x=-4
*) Ta có 2x-3=2(x+1)-5
=> 5 chia hết cho x+1
=> x+1 C Ư(5)={-5;-1;1;5}
Ta có bảng
| x+1 | -5 | -1 | 1 | 5 |
| x | -6 | -2 | 0 | 4 |
E
7 tháng 4 2020
B1.
2x - 5 = -x - 17
2x + x = -17 + 5
3x = -12
x = (-12) : 3
x = -4
Vậy x = -4
B2.
x + 1 là ước của 2x - 3
2x - 3 chia hết cho x + 1
( 2x + 2 ) - 5 chia hết cho x + 1
2( x + 1 ) - 5 chia hết cho x + 1
Vì x + 1 chia hết cho x + 1
nên 2(x+1) chia hết cho x + 1
Suy ra: 5 chia hết cho x + 1
Suy ra: x + 1 thuộc { 1; -1; 5; -5 }
Suy ra: x thuộc { 0 ; -2 ; 4; -6 }
Vậy x thuộc { 0 ; -2 ; 4; -6 }
Hok tốt !
\(17⋮x-2\)
\(\Rightarrow x-2\inƯ\left(17\right)=\left\{\pm1;\pm17\right\}\)
\(\Rightarrow x-2=1;-1;17;-17\)
\(\Rightarrow x=3;1;19;-15\)
Đề bài : Tìm số nguyên x?
Ta có : x-2 là ước của 17
\(\Rightarrow x-2\inƯ\left(17\right)=\left\{\pm1;\pm17\right\}\)
\(\Rightarrow x\in\left\{1;3;-15;19\right\}\)
Vậy x\(\in\){1;3;-15;19}