/x/ - 3.2 = 0
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a) \(0,{1^{2x - 1}} \le 0,{1^{2 - x}} \Leftrightarrow 2x - 1 \ge 2 - x \Leftrightarrow 3x \ge 3 \Leftrightarrow x \ge 1\)
b) \({3.2^{x + 1}} \le 1 \Leftrightarrow {2^{x + 1}} \le \frac{1}{3} \Leftrightarrow x + 1 \le {\log _2}\frac{1}{3} \Leftrightarrow x \le - {\log _2}3 - 1 = - {\log _2}3 - {\log _2}2 = - {\log _2}6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow2^{-3}.2^{2x}-3.2^{-2}.2^x+1=0\)
\(\Leftrightarrow\dfrac{1}{8}2^{2x}-\dfrac{3}{4}2^x+1=0\)
Đặt \(2^x=t>0\)
\(\Rightarrow\dfrac{1}{8}t^2-\dfrac{3}{4}t+1=0\Rightarrow\left[{}\begin{matrix}t=4\\t=2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2^x=4\\2^x=2\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=2\\x=1\end{matrix}\right.\)
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7x - x = 521 : 519 + 3. 22 - 70
(7-1)x=52 + 3. 4 - 1
6x = 25 + 12 - 1
6x = 36
x = 6
![](https://rs.olm.vn/images/avt/0.png?1311)
=> 2x = 6
x = 6:2
x = 3
Mà 3 > 0 => không có giá trị x âm để 2x-0.4= 3.2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^{x-2}-3.2^x=-88\)
\(2^x:2^2-2^x:\frac{1}{3}=-88\)
\(2^x:\left(2^2-\frac{1}{3}\right)=-88\)
\(2^x:\frac{11}{3}=-88\)
\(2^x=-88.\frac{11}{3}\)
\(2^x=\frac{-968}{3}\)
\(2^{x-2}-\)\(3.2^x=-88\)
\(2^x:2^2-2^x.3=-88\)
\(2^x.\frac{1}{4}-\)\(2^x.3=-88\)
\(2^x.\left(\frac{1}{4}-3\right)=-88\)
\(2^x.\frac{-11}{4}=-88\)
\(2^x=-88:\frac{-11}{4}\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(7x-x=5^{120}:5^{117}+3.2^2-7^0\)
\(6x=5^{120-117}+3.4-1\)
\(6x=5^3+12-1\)
\(6x=136\)
\(x=\frac{136}{6}=\frac{68}{3}\)
hok tốt!!
|x| - 3.2 = 0
|x| - 6 = 0
|x| = 6
=> x = +-6