Tìm x biết : -17 - |x- 5| = - 19
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a) Ta có: \(3-\left(17-x\right)=-12\)
\(\Leftrightarrow3-17+x+12=0\)
\(\Leftrightarrow x-2=0\)
hay x=2
Vậy: x=2
b) Ta có: \(\left(2x+4\right)\left(10-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+4=0\\10-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=-4\\2x=10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=5\end{matrix}\right.\)
Vậy: \(x\in\left\{-2;5\right\}\)c) Ta có: \(\left|x-9\right|=-2+17\)
\(\Leftrightarrow\left|x-9\right|=15\)
\(\Leftrightarrow\left[{}\begin{matrix}x-9=15\\x-9=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=24\\x=-6\end{matrix}\right.\)
Vậy: \(x\in\left\{24;-6\right\}\)
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\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+\frac{2}{17\times19}+\frac{2}{19\times21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)
\(\frac{10}{231}\times462-x=19\)
\(20-x=19\)
\(\Rightarrow x=20-19=1\)
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a) x+26=39+(-5)=34
x=34-26=8
b) IxI+50=(-I-26I)+76=(-26)+76=50
IxI=50-50=0
=> x=0
c) IxI+17=(-21)+19=-2
IxI=(-2)-17=-19
=> x thuộc tập hợp rỗng
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Gọi số phải tìm là A
=>A=17m+5=19n+12 (với m,n thuộc N)
=>3A+2=51m+17=57n+38
=>3A+2=17(3m+1)=19(3n+2)
=>3A+2 chia hết cho cả 17 và 19
=>3A+2=323
=>A=107
Vậy A=107
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16< x < 19
vì 16 < 17 < 18 < 19
vậy x = 17; 18
vì x là số chẵn vậy x = 18
Chọn C. 18
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a/ -x + 8 = -17-30
-x + 8 = -47
-x = -47 - 8
-x = -55
x = 55
Vậy x = 55
b/ 35 – x = 37
x = 35 - 37
x = -2
Vậy x = -2
c/ (-19 – x) + 23 = -20
-19 – x = -20 - 23
-19 – x = -43
x = -19 - (-43)
x = 24
Vậy x = 24
d/ (x – 45) : 2 = -17
x – 45 = -17 * 2
x – 45 = -34
x = -34 + 45
x = 11
Vậy x = 11
a/ -x + 8 = -17-30
-x + 8 = -47
-x =-47 - 8
-x = -55
x = 55
Vậy x = 55
Phần a mình bị lỗi nên sửa lại nha
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\(\dfrac{x}{17}+\dfrac{19}{34}=2\dfrac{1}{2}\)
\(\Rightarrow\dfrac{x}{17}+\dfrac{19}{24}=\dfrac{5}{2}\)
\(\Rightarrow\dfrac{x}{17}=\dfrac{33}{17}\Rightarrow x=33\)
-17-|x-5|=-19
|x-5|=(-17)-(-19)
|x-5|=2
\(\Rightarrow\orbr{\begin{cases}x-5=-2\\x-5=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=7\end{cases}}\)
Vậy x=3 hoặc x=7.