Rút gọn biểu thức: (x2+1)(x-3)-(x-3)(x2+1)
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( x 2 + 1 ) ( x − 3 ) − ( x − 3 ) ( x 2 − 1 ) = ( x – 3 ) x 2 + 1 – x 2 – 1 = 2 ( x – 3 )
x(2 x 2 – 3) – x 2 (5x + 1) + x 2
= x. 2 x 2 + x.(- 3) – ( x 2 . 5x + x 2 .1) + x 2
= (2 x 3 – 3x) – (5 x 3 + x 2 ) + x 2
= 2 x 3 – 3x – 5 x 3 – x 2 + x 2
= -3x – 3 x 3
1/2 x 2 (6x – 3) – x( x 2 + 1/2) + 1/2.(x + 4)
= (3 x 3 – 3/2. x 2 ) – ( x 3 + 1/2.x) + (1/2.x + 2)
= 3 x 3 - 3/2 x 2 – x 3 - 1/2 x + 1/2 x + 2
= ( 3 x 3 – x 3 ) - 3/2. x 2 – (1/2 x - 1/2 x) + 2
= 2 x 3 - 3/2 x 2 + 2
a. x(2x2 – 3) – x2(5x + 1) + x2
= 2x3 – 3x – 5x3 – x2 + x2 = -3x – 3x3
b. 3x(x – 2) – 5x(1 – x) – 8(x2 – 3)
= 3x2 – 6x – 5x + 5x2 – 8x2 + 24
= - 11x + 24
c. 1/2 x2(6x – 3) – x( x2 + 1/2 (x + 4)
= 3x3 - 3/2 x2 – x3 - 1/2 x + 1/2 x + 2
= 2x3 - 3/2 x2 + 2
a, x(2x2-3)-x2(5x+1)x2
=2x3-3x-5x3- x2+x2=-3x-3x3
học tốt nhé!!
\(A=\dfrac{x^2-2x-3-x^2+x-1+4x+4}{\left(x+1\right)\left(x^2-x+1\right)}\)
\(=\dfrac{3x}{\left(x+1\right)\left(x^2+x+1\right)}\)
3x(x – 2) – 5x(1 – x) – 8( x 2 – 3)
= 3x.x + 3x .( -2) – [5x.1 + 5x. (- x)] – [8 x 2 + 8.(- 3)]
= (3 x 2 – 6x) – (5x – 5 x 2 ) – (8 x 2 – 24)
= 3 x 2 – 6x – 5x + 5 x 2 – 8 x 2 + 24
= ( 3 x 2 +5 x 2 – 8 x 2 )- ( 6x + 5x) + 24
= - 11x + 24
\(A=x^2+4x-21-x^2-4x+5=-16\\ B=-2\left(4x^2+20x+25\right)-\left(1-16x^2\right)\\ B=-8x^2-40x-50-1+16x^2=8x^2-40x-51\\ C=x^2\left(x^2-16\right)-\left(x^4-1\right)=x^4-16x^2-x^4+1=1-16x^2\\ D=x^3+1-\left(x^3-1\right)=2\\ E=x^3-3x^2+3x-1-x^3+1-9x^2+1=-12x^2+3x+1\)
\(a,x^2+4x-21-x^2-4x+5=-16\\ b,=\left(x+8-x+2\right)^2=10^2=100\\ c,=x^2\left(x^2-16\right)-\left(x^4-1\right)\\ =x^4-16x^2-x^4+1=1-16x^2\\ d,=x^3+1-x^3+1=2\)
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