2^25.49^3
__________
14^8.8^4
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\(\dfrac{2^{15}\cdot9^4}{6^8\cdot8^3}=\dfrac{2^{15}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^8\cdot\left(2^3\right)^3}=\dfrac{2^{15}\cdot3^8}{2^8\cdot3^8\cdot2^9}=\dfrac{2^{15}\cdot3^8}{2^{17}\cdot3^8}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
\(\dfrac{2^{15}.9^4}{6^8.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^8.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^8.3^8.2^9}=\dfrac{2^{15}}{2^{17}}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
a, 48.84
= (22)8.(23)4
= 216.212
= 228
b, 415.515
= (4.5)15
= 2015
c, 210.15 + 210.85
= 210.(15 + 85)
= 210.100
=210.(2.5)2
= 212.52
d, 33.92
= 33 . (32)2
= 33.34
= 37
e, 512.7 - 511.10
= 511.(5.7 - 10)
= 511.25
=511.52
=513
f, \(x^1\).\(x^2\).\(x^3\)....\(x^{100}\)
= \(x^{1+2+3+...+100}\)
= \(x^{\left(1+100\right).100:2}\)
= \(x^{5050}\)
a) \(\frac{125^{100}.2^{160}}{5^{289}.4^{80}}=\frac{\left(5^3\right)^{100}.2^{160}}{5^{289}.\left(2^2\right)^{80}}=\frac{5^{300}.2^{160}}{5^{289}.2^{160}}=5^{300-289}=5^{11}\)
b) \(\frac{9^8.8^8}{3^8.27^3.2^{24}}=\frac{\left(3^2\right)^8.\left(2^3\right)^8}{3^8.\left(3^3\right)^3.2^{24}}=\frac{3^{16}.2^{24}}{3^8.3^9.2^{24}}=\frac{3^{16}}{3^{17}}=\frac{1}{3}\)
a) \(\frac{125^{100}.2^{160}}{5^{289}.4^{80}}=\frac{\left(5^3\right)^{100}.2^{160}}{5^{289}.\left(2^2\right)^{80}}=\frac{5^{300}.2^{160}}{5^{289}.2^{160}}=5\)
b) \(\frac{9^8.8^8}{3^8.27^3.2^{24}}=\frac{\left(3^2\right)^8.\left(2^3\right)^8}{3^8.\left(3^3\right)^3.2^{24}}=\frac{3^{16}.2^{24}}{3^8.3^9.2^{24}}=\frac{3^{16}.2^{24}}{3^{17}.2^{24}}=\frac{1}{3}\)
a )
\(\frac{-1}{5}.\frac{1}{2}=\frac{\left(-1.1\right)}{5.2}=\frac{-1}{10}\)
b )
\(\frac{-1}{8}.\frac{8}{9}=\frac{-1.1}{1.9}=\frac{-1}{9}\)
c )
\(\frac{-3}{7}.\frac{14}{15}=\frac{-1.2}{1.3}=\frac{-2}{3}\)
e )
\(\left(-4\right).\frac{7}{24}=\frac{-28}{24}=\frac{-7}{6}\)
f )
\(\frac{-9}{13}.\frac{-5}{18}=\frac{\left(-1\right).\left(-5\right)}{13.2}=\frac{6}{26}=\frac{3}{13}\)
đúng đó , tk mk nhé ! hihiii
a,\(\frac{-1}{10}\) b,\(\frac{-1}{9}\) c,\(\frac{-2}{5}\) e,\(\frac{-7}{6}\) f,\(\frac{-5}{26}\)
\(Ta\)\(có\):\(\frac{2^{25}.49^3}{14^8.8^4}\)
\(=\frac{2^{25}.(7^2)^3}{7^8.2^8.(2^3)^4}\)
\(=\frac{2^{25}.7^6}{7^8.2^{20}}\)
\(=\frac{2^5}{7^2}\)
\(=\frac{32}{49}\)
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