4^x+4^x+2=68
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Ta có: \(\left(2x+3\right)\left(x-4\right)+\left(x+5\right)\left(x-2\right)=\left(3x-5\right)\left(x-4\right)\)
\(\Leftrightarrow2x^2-8x+3x-12+x^2-2x+5x-10=3x^2-12x-5x+20\)
\(\Leftrightarrow-2x-22+17x-20=0\)
\(\Leftrightarrow15x=42\)
hay \(x=\dfrac{14}{5}\)
`(1 xx 2 xx 3 xx 4)/(3 xx 4 xx 5 xx 6)`
`= (1 xx 2)/(5 xx 6)`
`= 2/12`
`= 1/6`
`-2/5 : x=1/2`
`=> x= -2/5 : 1/2`
`=> x= -2/5 xx 2`
`=>x= -4/5`
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`7/6 : x = 7/4`
`=>x= 7/6 : 7/4`
`=>x=7/6 xx 4/7`
`=>x= 28/42`
`=>x=2/3`
\(\left(3x-4\right)^2=\left(x+2\right)^2\)
\(\Leftrightarrow\left(3x-4\right)^2-\left(x+2\right)^2=0\)
\(\Leftrightarrow\left(3x-4-x-2\right)\left(3x-4+x+2\right)=0\)
\(\Leftrightarrow\left(2x-6\right)\left(4x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x-6=0\\4x-2=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=\frac{1}{2}\end{cases}}\)
\(\dfrac{-4}{7}:x=\dfrac{-2}{5}\)
\(\Rightarrow x=\dfrac{-4}{7}:\dfrac{-2}{5}\)
\(\Rightarrow x=\dfrac{10}{7}\)
\(\dfrac{-4}{7}:x=\dfrac{-2}{5}\)
\(x=\dfrac{-4}{7}.\dfrac{-5}{2}\)
\(x=\dfrac{10}{7}\)
2 + 4 + 6 + ... + x = 110
=> \(\frac{\left(x+2\right)\left[\left(x-2\right):2+1\right]}{2}=110\)
\(\Rightarrow\left(x+2\right).\frac{1}{2}x=220\)
\(\Rightarrow\left(x+2\right)x=440\)
Mà 20 . 22 = 440
=> x = 20
Ta có : 2 + 4 + 6 +... + x = 110
=> [(x - 2) : 2 + 1].(x + 2) : 2 = 110
=> \(\left(\frac{x}{2}-1+1\right).\left(\frac{x+2}{2}\right)=110\)
=> \(\frac{x}{2}.\frac{x+2}{2}=110\)
=> \(\frac{x\left(x+2\right)}{4}=110\)
=> x(x + 2) = 440
=> x2 + 2x = 440
=> x2 + 2x + 1 = 441
=> x2 + x + x + 1 = 441
=> x(x + 1) + (x + 1) = 441
=> (x + 1)2 = 441
=> (x + 1)2 = 212
=> x + 1 = 21
=> x = 20
Vậy x = 20
\(4^x+4^{x+2}=68\)
\(\Rightarrow4^x+4^{x+2}=4^3+4\)
\(\Rightarrow x+2=3\)
\(\Rightarrow x=1\)
Vậy x = 1
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