a) [3.(70-x ) +5 ] :2 = 17
b)3^x+2-5.3^x
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\(6^2-\left(x+3\right)=45\)
\(36-\left(x+3\right)=45\)
\(x+3=35-45\)
\(x+3=-10\)
\(x=-13\)
5.3x = 5.34
=> x = 4
5.34 = 7.35 - 2.35
= 35 . (7 - 2)
= 5. 35
=> 3x = 35
=> x = 5
2(x4+3)-(9)=17
⇒2x4+6+9=17
⇒2x4+15=17
⇒ 2x4=2
⇒ x4=1
⇒ x=\(\pm1\)
b) 5x2.x+1-3.42=-47
⇒5x3+1-48=-47
⇒5x3-47=-47
⇒5x3=0
⇒x3=0
⇒x=0
a) \(2\left(x^4+3\right)-\left(-9\right)=17\)
\(2x^4+6+9=17\)
\(2x^4=2\)
\(x^4=1\)
⇒ \(x=1\)
c, \(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)
\(\Leftrightarrow5^{x+3}\cdot5-3\cdot5^{x+3}=2\cdot5^{11}\)
\(\Leftrightarrow5^{x+3}\left(5-3\right)=2\cdot5^{11}\)
\(\Leftrightarrow5^{x+3}\cdot2=2\cdot5^{11}\)
\(\Leftrightarrow5^{x+3}=5^{11}\)
\(\Leftrightarrow x+3=11\)
\(\Leftrightarrow x=8\)
Vậy x = 8
d, \(2^x+2^{x+1}+2^{x+2}+2^{x+3}+2^{x+4}+2^{x+5}=480\)
\(\Leftrightarrow2^x\left(1+2+2^2+2^3+2^4+2^5\right)=480\)
\(\Leftrightarrow2^x\cdot63=480\)
\(\Leftrightarrow2^x=\frac{160}{21}\)
\(\Leftrightarrow x\approx2,93\)
a: Ta có: \(x\left(2x-3\right)-\left(2x-1\right)\left(x+5\right)=17\)
\(\Leftrightarrow2x^2-3x-2x^2-10x+x+5=17\)
\(\Leftrightarrow-12x=12\)
hay x=-1
1; 5.22 + (\(x\) + 3) = 52
5.4 + (\(x\) + 3) = 25
20 + (\(x\) + 3) = 25
\(x\) + 3 = 25 - 20
\(x+3\) = 5
\(x\) = 5 - 3
\(x\) = 2
Vậy \(x=2\)
2; 23 + (\(x\) - 32) = 53 - 43
8 + (\(x\) - 9) = 125 - 64
8 + (\(x\) - 9) = 61
\(x\) - 9 = 61 - 8
\(x\) - 9 = 53
\(x\) = 53 + 9
\(x\) = 62
Vậy \(x\) = 62
a) 3x-1=-17
<=>3x=-16
<=>x=-16/3
Vậy...
b) 40-(3x-8)=3(3-5x)
<=>40-3x+8=9-15x
<=>12x = -39
<=> x = -13/4
Vậy ...
c) x/2(x-2) + x/2x+2 = 2x/(x+1)(x-2)
<=> x/2(x-2) + x/2(x+1) = 2x/(x+1)(x-2)
<=> x(x+1)/2(x-2)(x+1) + x(x-2)/2(x+1)(x-2) = 4x/2(x+1)(x-2)
=>x(x+1) + x(x-2) = 4x
<=> x2 + x + x2 -2x = 4x
<=> 2x^2 -5x = 0
<=> x(2x-5) = 0
<=>x=0 hoặc 2x-5=0
<=>x=0 <=>x=5/2
Vậy...
(Nhớ tick mik nha)
a: =>3x=-16
=>x=-16/3
b: =>40-3x+8=9-15x
=>-3x+48=9-15x
=>12x=-39
=>x=-13/4
c: =>x(x+1)+x(x-2)=4x
=>x^2+x+x^2-2x-4x=0
=>2x^2-5x=0
=>x=0 hoặc x=5/2
ko ghi lại đề nha :))
a) (210 - 3x +5) = 17 . 2
-3x + 215 = 34
-3x = -181
x = 181 / 3