Phép tính:

\(2\times\sqrt{15}-2\times\sqrt{10}+\sqrt{6}=1421411372\)

\(2\times\sqrt{15}-2\times\sqrt{10}+\sqrt{3}+\sqrt{6}=5602951922\)

P/s: Em ko biết đúng hay sai đâu mới lớp 4 thôi à

\(B=\dfrac{7.2^{10}.3^{10}2.^{21}.3^6-2^{19}.2^{15}.3^{15}}{3^2.2^{15}.3^{15}.2^{13}-2^2.3^{15}.2^{26}}=\)

\(=\dfrac{2^{31}.3^{15}\left(7.3-2^3\right)}{2^{28}.3^{15}\left(3^2-1\right)}=\dfrac{2^{31}.13}{2^{31}}=13\)

giúp mình với huhu

ta có : (ghi lại đề)

=6+12+18+24+30/3+6+9+12+15

=2*(3/3+6/6+9/9+12/12+15/15)

=2*(1+1+1+1+1)

=2*5=10

chúc main học tốt nhé

hi

1x2x3x4x5x6x7x8x9

2x3x4x5x6x7x8x9x10

=1/10

b)1/2*2/3*3/4*4/5*5/6*6/7*7/8*8/9*9/10

=1x2x3x4x5x6x7x8x9

  2x3x4x5x6x7x8x9x10

= 1

  10

A. 3/6; 9/6; 1/3

B. 2/3; 8/6; 4/10

C. 10/15; 2/3; 8/12

D. 9/15; 2/3; 12/10

đáp án C là đúng nhé

  ~~~~~   hok tốt~~~

\(\dfrac{2\sqrt{15}-2\sqrt{10}-3+\sqrt{6}}{2\sqrt{5}-2\sqrt{10}-\sqrt{3}+\sqrt{6}}\)

\(=\dfrac{2\sqrt{5}\left(\sqrt{3}-\sqrt{2}\right)-\sqrt{3}\left(\sqrt{3}-\sqrt{2}\right)}{2\sqrt{5}\left(1-\sqrt{2}\right)-\sqrt{3}\left(1-\sqrt{2}\right)}\)

\(=\dfrac{\sqrt{3}-\sqrt{2}}{1-\sqrt{2}}=-\sqrt{3}-\sqrt{6}+\sqrt{2}+2\)

tín https://www.facebook.com/docbaoonlinethayban/videos/467035000526358/?v=467035000526358 Cả nhà tải ngay bằng link dưới đây nhé. https://giaingay.com.vn/downapp.html

Nguyễn Nhật Minh

Ta có: \(\dfrac{\left(-3\right)^6\cdot15^5+9^3\cdot\left(-15\right)^6}{\left(-3\right)^{10}\cdot5^5\cdot2^3}\)

\(=\dfrac{3^6\cdot3^5\cdot5^5+3^6\cdot3^6\cdot5^6}{3^{10}\cdot5^5\cdot2^3}\)

\(=\dfrac{3^{11}\cdot5^5+3^{11}\cdot3\cdot5^5\cdot5}{3^{10}\cdot5^5\cdot2^3}\)

\(=\dfrac{3^{11}\cdot5^5\left(1+3\cdot5\right)}{3^{10}\cdot5^5\cdot2^3}\)

\(=\dfrac{3\cdot9}{8}=\dfrac{27}{8}\)

đoạn cuối thấy sai sai phải là 3.16 chứ