(x+4).(x+4)=5.20
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Bài 2:
a) x + 5,7 = 18,6 - 10,3
x + 5,7 = 8,3
x = 8,3 - 5,7
x = 3,6
b) 6,4 . x = 5 . 3,2
6,4 . x = 16
6,4 . x = 16 : 6,4
6,4 . x = 2,5
B1
a) 3/5 . 20/18 : 2/9 .1/15
= 3/5 . 20/18 . 9/2 .1/15
= (3/5 . 1/15) . (20/18 . 9/2)
= 1/25 . 5
= 1/5
b. (5/2 + 1/8) : (1 - 7/16)
= 21/8 : 9/16
= 21/8 . 16/9
= 14/3
B2:
\(a.x+5,7=18,6-10,3\\ x=18,6-10,3-5,7\\ x=18,6-\left(10,3+5,7\right)\\ x=18,6-16\\ x=2,6\\ b.6,4\cdot x=5\cdot3,2\\ \left(3,2\cdot2\right)\cdot x=5\cdot3,2\\ x=\dfrac{5}{2}\cdot\left(3,2:3,2\right)\\ x=\dfrac{5}{2}\)
c) x + 2/4 = 15/9 + 3/36
x + 2/4 = 7/4
x = 7/4 - 2/4
x = 5/4
d) x . 4/3 = 15/3 - 22/6
x . 4/3 = 4/3
x = 4/3 :4/3
x = 1
B4:
Gọi số đầu tiên là a
Vì tổng của 4 số tự nhiên liên tiếp = 2010
=> a + (a+1) + (a+2) + (a+3) =2010
=> a4 + 6 = 2010
=> a4 = 2004
=> a = 501
Số thứ 2 là:
501 + 1 = 502
Số thứ 3 là:
502 + 1 = 503
Số thứ 4 là :
503 + 1 = 504
1. fifteen past nine
2. ten to two
3. twelve
4. twenty past five
2. ten to two
1. fifteen past nine
3. twelve
4. twenty past five
1,
\(75-\left(3.5^2-4.2^3\right)=75-\left(75-32\right)=75-75+32=32\)
2,
\(58.76+24.58-5.20=58\left(76+58\right)-100=58.100-100=100\left(58-1\right)=5700\)3,
\(4.5^2-3.2^3+3^3:3^2=4.5^2-3.2^3+3^{3-2}=3\left(2^3+1\right)+100=27+100=127\)4,
\(\left[5^2.6-20\left(37-2^5\right)\right]:10-10^0=\left(5^2.6-20.5\right):10-1=\left[10\left(15-10\right)\right]:10-1=5-1=4\)cái đề bn ghi ko rõ nên mk lầm thì báo mk nhé
9 hours and 15 minutes ( nine hours and five minutes )
1 hours and 50 minutes ( one hours and fifty minutes )
12 hours ( twelve o'clock )
5 hours 20 minutes ( five hours and twenty minutes )
a)\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{3^3\cdot2^3+3^3\cdot2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=-3^3=-27\)
b) \(\frac{2^3+3\cdot2^6-4^3}{2^3+3^2}=\frac{8+3\cdot64-64}{8+9}=\frac{8+192-64}{17}=\frac{136}{17}=8\)
c) \(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}=\frac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\frac{2^{11}\cdot3^{10}\left(2+2\cdot5\right)}{2^{11}\cdot3^{10}\cdot\left(2\cdot3^2-3\right)}=\frac{12}{18-3}=\frac{12}{15}\)
d) \(\frac{5^5\cdot20^3-5^4\cdot20^3+5^7\cdot4^5}{\left(20+5\right)^3\cdot4^5}=\frac{5^5\cdot20^3-5^4\cdot20^3+20^3\cdot20^2\cdot5^2}{5^6\cdot4^5}=\frac{20^3\left(5^5-5^4+5^4\cdot4^2\right)}{20^5\cdot5}\)\(=\frac{5^4\left(5-1+16\right)}{20^2\cdot5}=\frac{5^4\cdot20}{20^2\cdot5}=\frac{5^3}{20}=\frac{5^3}{5\cdot4}=\frac{25}{4}\)
Bài giải
a)\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{3^3\cdot2^3+3^3\cdot2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=-3^3=-27\)
b) \(\frac{2^3+3\cdot2^6-4^3}{2^3+3^2}=\frac{8+3\cdot64-64}{8+9}=\frac{8+192-64}{17}=\frac{136}{17}=8\)
c) \(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}=\frac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\frac{2^{11}\cdot3^{10}\left(2+2\cdot5\right)}{2^{11}\cdot3^{10}\cdot\left(2\cdot3^2-3\right)}=\frac{12}{18-3}=\frac{12}{15}\)
d) \(\frac{5^5\cdot20^3-5^4\cdot20^3+5^7\cdot4^5}{\left(20+5\right)^3\cdot4^5}=\frac{5^5\cdot20^3-5^4\cdot20^3+20^3\cdot20^2\cdot5^2}{5^6\cdot4^5}=\frac{20^3\left(5^5-5^4+5^4\cdot4^2\right)}{20^5\cdot5}\)\(=\frac{5^4\left(5-1+16\right)}{20^2\cdot5}=\frac{5^4\cdot20}{20^2\cdot5}=\frac{5^3}{20}=\frac{5^3}{5\cdot4}=\frac{25}{4}\)
(x+4).(x+4)=5.20
(x+4)2=100
x+4=\(\sqrt{100}\)
x+4=10
x=10-4
x=6
=> (x+4)2=100
=> (x+4)2=102=(-10)2
+) x+4=10
=> x=10-4
=> x=6
+) x+4=-10
=> x=-10-4
=> x=-14
Vậy \(x\in\left\{-14;6\right\}\).