Question

[Linh Khanh]

mọi ngừi giúp mình vs ạ!!!!

Answer 1

[Hoàng Như Quỳnh]

\(\left(x^2+x\right)^2+x^2=\left(x+1\right)^2\)

\(\left(x^2+x-x-1\right)^2+x^2=0\)

\(\left(x^2-1\right)^2+x^2=0\)

\(\hept{\begin{cases}\left(x^2-1\right)^2\ge0\\x^2\ge0\end{cases}}\Rightarrow\left(x^2-1\right)^2+x^2\ge0\)

để \(\left(x^2-1\right)^2+x^2=0\)

\(\Rightarrow\hept{\begin{cases}\left(x^2-1\right)^2=0\\x^2=0\end{cases}\hept{\begin{cases}x^2=1\\x^2=0\end{cases}\hept{\begin{cases}x=1\\x=0\end{cases}\Rightarrow}}}\left(KTM\right)\)

vậy pt vô nghiệm