4/7x = 9/8 - 0,125
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a/
3/4 . x = 1
=> x= 1: 3/4 = 4/3
b/
4/7 .x = 9/8 -0,125 = 9/8 -1/8 = 1
=> x= 1 : 4/7 = 7/4
a/ 3/4x=1
x=1:3/4
x=4/3
b/ 4/7x=9/8-0,125
4/7x=1
x=1:4/7
x=7/4
Lời giải:
a)
\(\frac{3}{4}x=1\)
\(x=1:\frac{3}{4}=1.\frac{4}{3}=\frac{4}{3}\)
b)
\(\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=1\)
\(x=1:\frac{4}{7}\)
\(x=\frac{7}{4}\)
a) 3/4x = 1
x = 1 : 3/4
x = 4/3
b) 4/7x = 9/8 - 0,125
4/7x = 1
x = 1 : 4/7
x = 7/4
*4/7x=9/8.0,125
4/7x=9/8.1/8
4/7x=9/64
x =9/64:4/7
x =9/64.7/4
x =63/256
*x-25%=1/2
x-1/4.x =1/2
x(1-1/4) =1/2
3/4.x =1/2
x =1/2:3/4
x =1/2.4/3
x =2/3
a,\(\frac{1}{7}\)b,\(\frac{7}{4}\)c,\(\frac{-10}{3}\)d,ko rõ e,=10
\(\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}\left(\dfrac{1}{8}=0,125\right)\)
\(\dfrac{4}{7}x=1\)
->x=1:\(\dfrac{4}{7}\)
-> x= \(\dfrac{7}{4}\)
Ta có: \(\dfrac{4}{7}x=\dfrac{9}{8}-0.125\)
\(\Leftrightarrow\dfrac{4}{7}x=\dfrac{9}{8}-\dfrac{1}{8}=1\)
hay \(x=\dfrac{7}{4}\)
Vậy: \(x=\dfrac{7}{4}\)
4/7x = 9/8 - 0,125
4/7x = 9/8 - 1/8
4/7x = 1
x = 1 : 4/7
x = 7/4
=^_^=
k mình nha
\(\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{4}{7}x=\frac{8}{8}\)
\(\frac{4}{7}x=1\)
\(x=1:\frac{4}{7}\)
\(x=1\times\frac{7}{4}\)
\(x=\frac{7}{4}\)