\(\frac{2x+\frac{3x-4}{5}}{15}\) < \(\frac{\frac{3-x}{2}+7x}{5}\) + 1 - x
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T
0
B
1
MN
28 tháng 2 2020
\(\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x-\frac{x-3}{2}}{5}-x+1\)
\(\Leftrightarrow\frac{2x}{15}-\frac{4-3x}{75}=\frac{7x}{5}-\frac{x-3}{10}-x+1\)
\(\Leftrightarrow\frac{2x}{15}-\frac{4-3x}{75}-\frac{7x}{5}+\frac{x-3}{10}+x-1=0\)
\(\Leftrightarrow\frac{20x-2\left(4-3x\right)-210x+15\left(x-3\right)+150x-150}{150}=0\)
\(\Leftrightarrow20x-8+6x-210x+15x-45+150x-150=0\)
\(\Leftrightarrow-19x-203=0\)
\(\Leftrightarrow x=-\frac{203}{19}\)
Vậy tập nghiệm của phương trình là \(S=\left\{-\frac{203}{19}\right\}\)
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A
1 tháng 3 2020
\(\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x-\frac{x-3}{2}}{5}-x+1\)
\(\Leftrightarrow\frac{2x}{15}-\frac{\frac{4-13x}{5}}{15}=\frac{7x}{5}-\frac{\frac{x-3}{2}}{5}-x+15\)
\(\Leftrightarrow\frac{2x}{15}-\frac{4-3x}{75}=\frac{7x}{5}-\frac{x-3}{10}-x+1\)
\(\Leftrightarrow\frac{2x}{15}-\frac{4-3x}{75}=\frac{2x}{5}-\frac{x-3}{10}+1\)
\(\Leftrightarrow20x-2\left(4-3x\right)=60x-15\left(x-3\right)+150\)
\(\Leftrightarrow20x-8+6x=60x-15x+45+150\)
\(\Leftrightarrow26x-8=49x+195\)
\(\Leftrightarrow-8=45x+195-26x\)
\(\Leftrightarrow-8=19x+195\)
\(\Leftrightarrow-8-195=19x\)
\(\Leftrightarrow-203=19x\)
\(\Leftrightarrow x=-\frac{203}{19}\)
vậy: tập nghiệm của phương trình là: \(S=\left\{-\frac{203}{19}\right\}\)
6 tháng 2 2020
\(b,\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x-\frac{x-3}{2}}{5}-x+1\)
\(\Leftrightarrow\frac{2x}{15}-\frac{4-3x}{75}=\frac{7x}{5}-\frac{x-3}{10}-x+1\)
\(\Leftrightarrow\frac{10.2x}{150}-\frac{2\left(4-3x\right)}{150}=\frac{30.7x}{150}-\frac{15\left(x-3\right)}{150}-\frac{150\left(x-1\right)}{150}\)
\(\Leftrightarrow2x-8+6x=210x-15x+45-150x+150\)
\(\Leftrightarrow-19x=203\)
\(\Leftrightarrow x=-\frac{203}{19}\)
Vậy ............
T
1 tháng 5 2019
\(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{6}\)
\(\Leftrightarrow\frac{\left(9x-0,7\right)\cdot7}{4\cdot7}-\frac{\left(5x-1,5\right)\cdot4}{7\cdot4}=\frac{7x-1,1-2+10x}{6}\)
\(\Leftrightarrow\frac{63x-4,9-20x+6}{28}=\frac{7x-1,1-2+10x}{6}\)
\(\Leftrightarrow\left(63x-4,9-20x+6\right)\cdot6=28\left(7x-1,1-2+10x\right)\)
\(\Leftrightarrow378x-120x+6,6=196x-86,8+280x\)
\(\Leftrightarrow378x-120x-196x-280x=-86,8-6,6\)
\(\Leftrightarrow-218x=-93,4\)
\(\Leftrightarrow x=\frac{467}{1090}\)
28 tháng 5 2019
\(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\)
\(\Rightarrow\frac{3\left(5x-1\right)}{30}+\frac{5\left(2x+3\right)}{30}=\frac{2\left(x-8\right)}{30}-\frac{x}{30}\)
\(\Rightarrow15x-3+10x+15=2x-16-x\)
\(\Rightarrow24x=-28\)
\(\Rightarrow x=-\frac{7}{6}\)
PN
2 tháng 7 2020
\(\frac{25x-655}{95}-\frac{5\left(x-12\right)}{209}=\frac{89-3x-\frac{2\left(x-18\right)}{5}}{11}\)
\(< =>\frac{5x-131}{19}=\frac{1631-52x-\frac{38x-684}{5}}{209}\)
\(< =>\left(5x-131\right)209=\left(1631-52x-\frac{38x-684}{5}\right)19\)
\(< =>55x-1441=1631-52x-\frac{38x-684}{5}\)
\(< =>3072-107x=\frac{38x-684}{5}\)
\(< =>\left(3072-107x\right)5=38x-684\)
\(< =>15360-535x-38x-684=0\)
\(< =>14676=573x< =>x=\frac{14676}{573}=\frac{4892}{191}\)
nghệm xấu thế
PN
2 tháng 7 2020
\(\frac{8\left(x+22\right)}{45}-\frac{7x+149+\frac{6\left(x+12\right)}{5}}{9}=\frac{x+35+\frac{2\left(x+50\right)}{9}}{5}\)
\(< =>\frac{8x+176}{45}-\frac{41x+817}{45}=\frac{11x+415}{45}\)
\(< =>993-33x-11x-415=0\)
\(< =>578=44x< =>x=\frac{289}{22}\)
* \(\frac{2x+\frac{3x-4}{5}}{15}=\frac{\frac{10x+3x-4}{5}}{15}=\frac{13x-4}{5}.\frac{1}{15}=\frac{13x-4}{75}\)
*\(\frac{\frac{3-x}{2}+7x}{5}=\frac{\frac{3-x+14x}{2}}{5}=\frac{\frac{3+13x}{2}}{5}=\left(\frac{3+13x}{2}.\frac{1}{5}\right)=\frac{3+13x}{10}\)
➝\(\frac{\frac{3-x}{2}+7x}{5}+1-x=\frac{3+13x}{10}+1-x=\frac{3+13x+10\left(1-x\right)}{10}=\frac{13+3x}{10}\)BPT⇔\(\frac{13x-4}{75}< \frac{13+3x}{10}\)
⇔\(\frac{13x}{75}+\frac{3x}{10}< \frac{13}{10}+\frac{4}{75}\)
⇔\(\frac{-19x}{150}< \frac{203}{150}\)
⇔\(x>\frac{-203}{19}\approx-10.68\)