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x+4/7+y = 4/7
=> (x + 4)7 = 4(y + 7)
=> 7x + 28 = 28 + 4y
=> 7x = 4y
=> x/4 = y/7
=> x + y/4 + 7 = x/4 = y/7 mà x + y = 77
=> 77/11 = x/4 = y/7
=> 7 = x/4 = y/7
=> x = 28; y = 49
1a) \(\frac{x-3}{x+7}=\frac{-5}{-6}\)
=> \(\frac{x-3}{x+7}=\frac{5}{6}\)
=> (x - 3).6 = 5.(x + 7)
=> 6x - 18 = 5x + 35
=> 6x - 5x = 35 + 18
=> x = 53
b) \(\frac{x-7}{x+3}=\frac{4}{3}\)
=> (x - 7). 3 = (x + 3). 4
=> 3x - 21 = 4x + 12
=> 3x - 4x = 12 + 21
=> -x = 33
=> x = -33
c) \(\frac{x-10}{6}=-\frac{5}{18}\)
=> (x - 10) . 18 = -5 . 6
=> 18x - 180 = -30
=> 18x = -30 + 180
=> 18x = 150
=> x = 150 : 18 = 25/3
d) \(\frac{x-2}{4}=\frac{25}{x-2}\)
=> (x - 2)(x - 2) = 25 . 4
=> (x - 2)2 = 100
=> (x - 2)2 = 102
=> \(\orbr{\begin{cases}x-2=10\\x-2=-10\end{cases}}\)
=> \(\orbr{\begin{cases}x=12\\x=-8\end{cases}}\)
e) \(\frac{7}{x}=\frac{x}{28}\)
=> 7 . 28 = x . x
=> 196 = x2
=> x2 = 142
=> \(\orbr{\begin{cases}x=14\\x=-14\end{cases}}\)
f) \(\frac{40+x}{77-x}=\frac{6}{7}\)
=> (40 + x) . 7 = (77 - x).6
=> 280 + 7x = 462 - 6x
=> 280 - 462 = -6x + 7x
=> -182 = x
=> x = -182
a) x = -3
b) x = -7
c) x = 4
y = 14
d) x = 16
y = 1
a, x/5=6/-10
-x/-5=6/-10
-2x/-10=-6/-10
-2x=6
x=-3
b,3/y=33/77
11.3/11.y=33/77
33/11.y=33/77
11.y=77
y=7
c,x/3=4/y
x.y=4.3
xy=12
x=3,y=4. x=-3,y=-4. x=1, y=12. x=-1,y=-12,...[tu lam not]
d,x/y=2/7
x=2a, y=7a [ a la so nguyen]
e,2/x=x/8
x.x=2.8
x.x=16
x=4
a) x=\(\dfrac{5.6}{-10}=-3.\)
b) y=\(\dfrac{3.77}{-33}=-7.\)
a: \(\Leftrightarrow x^2-2x+1+y^2+2y+1+z^2-4z+4=0\)
\(\Leftrightarrow\left(x-1\right)^2+\left(y+1\right)^2+\left(z-2\right)^2=0\)
=>x=1; y=-1; z=2
b: \(a^2\left(a+1\right)+2a\left(a+1\right)\)
\(=\left(a+1\right)\left(a^2+2a\right)\)
\(=a\left(a+1\right)\left(a+2\right)\)
Vì a;a+1;a+2 là ba số nguyên liên tiếp
nên \(a\left(a+1\right)\left(a+2\right)⋮3!\)
hay \(a\left(a+1\right)\left(a+2\right)⋮6\)
y=11
Chúc bạn học tốt
y x ( 6 + 1 ) = 77
y x 7 =77
y = 77 : 7
y = 11