2x + 3 . 2x = 128
Ai nhanh thì tick nhé ^^
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2x +1/2=-3
2x=(-3)-1/2
2x=-2,5
x= (-2,5)÷2
x=-1,25
còn lại mk chịu
Cbht
\(\frac{5-2x}{3}=\frac{4x-1}{-5}\)
-5(5-2x) = 3(4x-1)
-25 + 10x = 12x - 3
10x - 12x = -3 + 25
-2x = 22
x= -11
Nhân chéo như trên rồi tự làm nha
Học tốt~
\(7\left(3x-3\right)=\left(2x+2\right)3\)
\(21x-21=6x+6\)
\(21x-21-6x-6=0\)
\(15x-27=0\)
\(15x=27\)
\(x=\frac{27}{15}=\frac{9}{5}\)
7 ( 3 x - 3 ) = ( 2 x + 2 ) 3
4 (3 x - 3 ) = 2 x + 2
12 x - 12 = 2 x +2
2x +9x = 2x +2
2 = 9 x
=> x = 2 : 9
=> x = rỗng
Vậy x = rỗng
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
\(\Rightarrow x+\frac{1}{2}=0\) \(\Rightarrow\frac{2}{3}-2x=0\)
\(x=\frac{-1}{2}\) \(2x=\frac{2}{3}\)
\(x=\frac{2}{3}:2\)
\(x=\frac{1}{3}\)
KL: x = -1/2 hoặc x= 1/3
b) \(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=\frac{11}{6}\)
\(\left|2x-\frac{1}{3}\right|=1\)
TH1: \(2x-\frac{1}{3}=1\)
\(2x=\frac{4}{3}\)
\(x=\frac{2}{3}\)
TH2: \(2x-\frac{1}{3}=-1\)
\(2x=\frac{-2}{3}\)
\(x=\frac{-2}{3}:2\)
\(x=\frac{-1}{3}\)
KL: x =.........
Học tốt nhé bn!!!
a) \(5-\frac{2x}{3}=4x-\frac{1}{-5}\)
\(\frac{75-10x}{15}=\frac{60x+3}{15}\)
75 - 10x = 60x +3
72 = 70x
\(\frac{72}{70}\) = x
x =\(\frac{36}{35}\)
Vậy x = \(\frac{36}{35}\)
b) \(2x-\frac{10}{6}=\frac{-27}{5}-x\)
\(2x-\frac{5}{3}=\frac{-27}{5}-x\)
\(\frac{30x-25}{15}=\frac{-81-15}{15}\)
30x =-96+25
30x =-71
x= -71/30
Vậy x= -71/30
c) \(13x-\frac{2}{2x}+5=\frac{76}{17}\)
13x - 1/x +5 = 76/17
\(\frac{221x-17+85}{17x}=\frac{76x}{17x}\)
221x +68 = 76x
221x-76x =-68
145x =-68
x =\(\frac{-68}{145}\)
Vậy .........
a.8x+28-9x+6=24
<=> -x+34=24
<=> -x=24-34
<=> x=10
b. 3-6x-x-18=7
<=> -7x=7+18-3
<=> -7x=22
<=> x=22/-7
`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) * ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34-0\\2x=0+6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
\(\left(2019-x\right)\left(3x-12\right)=0\)
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=0+12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy,` x \in {2019; 4}`
p/s: Bài này hnhu mk làm r mà ạ?
\(\frac{2x}{3}-\frac{2}{y}=\frac{1}{3}\)
\(\Rightarrow\frac{2}{y}=\frac{2x-1}{3}\)
\(\Leftrightarrow y.\left(2x-1\right)=6\)
Tới đây tự lập bảng ra nhé!! hok tốt!!
a) 2x2+3x-5=0
=> 2x2+5x-2x-5=0
=> x(2x+5)-(2x-5)=0
=> (2x-5)(x-1)=0
=> 2x-5=0, x-1=0
=> x=5/2; 1
\(2x^2+3x-5=0< =>2x^2-2+3x-3=0\)
\(< =>2\left(x+1\right)\left(x-1\right)-3\left(x-1\right)=0\)
\(< =>\left(x-1\right)\left(2x-1\right)=0< =>\orbr{\begin{cases}x=1\\x=\frac{1}{2}\end{cases}}\)
2x.8+2x=128
2x.(8+1)=128
2x.9=128
2x\(\approx\)14,23
\(2^{x+3}.2^x=128\)
=> \(2^{x+3+x}=128\)
=> \(2^{2x+3}=2^7\)
=> 2x + 3 = 7
=> 2x = 7 - 3
=> 2x = 4
=> x = 2