9x3^3x1/81x3^2
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a: =>3^x=3^4*3=3^5
=>x=5
b: =>\(2^{x+1}=2^5\)
=>x+1=5
=>x=4
c: \(\Leftrightarrow3^{x+2-3}=3\)
=>x-1=1
=>x=2
d: \(\Leftrightarrow x^2=\dfrac{32}{2}=16\)
=>x=4 hoặc x=-4
e: (2x-1)^4=81
=>2x-1=3 hoặc 2x-1=-3
=>2x=4 hoặc 2x=-2
=>x=-1 hoặc x=2
f: (2x-6)^4=0
=>2x-6=0
=>x-3=0
=>x=3
a) \(3^x=81\cdot3\)
\(\Rightarrow3^x=3^4\cdot3\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
b) \(2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
c) \(3^{x+2}:27=3\)
\(\Rightarrow3^{x+2}:3^3=3\)
\(\Rightarrow3^{x+2-3}=3\)
\(\Rightarrow3^{x-1}=3\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=2\)
d) \(2x^2=32\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x^2=4^2\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
e) \(\left(2x-1\right)^4=81\)
\(\Rightarrow\left(2x-1\right)^4=3^4\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=3\\2x-1=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=4\\2x=-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
f) \(\left(2x-6\right)^4=0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=6:2\)
\(\Rightarrow x=3\)
\(a)4\cdot8\cdot16^2=2^2\cdot2^3\cdot\left(2^4\right)^2=2^5\cdot2^8=2^{13}\\ b)4^3\cdot64=\left(2^2\right)^3\cdot2^6=2^6\cdot2^6=2^{12}\\ c)3^4\cdot9\cdot27^2=3^4\cdot3^2\cdot\left(3^3\right)^2=3^4\cdot3^2\cdot3^6=3^{12}\\ d)16^2\cdot9^4=\left(2^4\right)^2\cdot\left(3^2\right)^4=2^8\cdot3^8=\left(2\cdot3\right) ^8=6^8\\ e)25\cdot5\cdot125=5^2\cdot5\cdot5^3=5^6\\ g)81\cdot3^3=3^4\cdot3^3=3^7\\ h)125^2\cdot25^4=\left(5^2\right)^2\cdot\left(5^2\right)^4=5^4\cdot5^8=5^{12}\\ i)4^2\cdot25=4^2\cdot5^2=\left(4\cdot5\right)^2=20^2\)
a) 2/9 : 2/3 x 1/2
= 2/9 x 3/2 x 1/2
= 6/18 x 1/2
= 6/36
b) 2 + 1/4 x 4/3
= 2 + 4/7
= 2/1(7) + 4/7
= 14/7 + 4/7
= 18/7
c) 3 x 1/2 x 1/4
= 3/1 x 1/2 x 1/4
= 3/2 x 1/4
= 3/8
#Hok_tốt
a: \(=\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}=\dfrac{31}{35}\)
b: \(=\dfrac{6}{5}+\dfrac{3}{2}\cdot\dfrac{1}{3}=\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{12+5}{10}=\dfrac{17}{10}\)
c: \(=\dfrac{5\cdot3}{9}=\dfrac{5}{3}\)
d: =5-2/3*6/5
=5-12/15
=5-4/5
=21/5
a) \(5x^3y\left(x-x^2y\right)=5x^4y-5x^5y^2\)
b) \(\left(27x^3-1\right):\left(9x^2+3x+1\right)\)
\(=\left(3x-1\right)\left(9x^2+3x+1\right):\left(9x^2+3x+1\right)\)
\(=3x-1\)
Đề câu b phải như này nha !
Lời giải của các bạn đều thỏa mãn yêu cầu đề bài là phân tích đa thức thành nhân tử
\(\dfrac{7}{3}\times\dfrac{1}{2}+\dfrac{1}{7}=\dfrac{7}{6}+\dfrac{1}{7}=\dfrac{49}{42}+\dfrac{6}{42}=\dfrac{55}{42}\)
\(\frac{1}{2}\)- \(\frac{1}{3}\)x \(\frac{1}{4}\)
= \(\frac{1}{2}\)- \(\frac{1}{12}\)
= \(\frac{6}{12}\)- \(\frac{1}{12}\)
= \(\frac{5}{12}\)
tk nhé
\(9\cdot3^3\cdot\dfrac{1}{81}\cdot3^2=\dfrac{3^7}{3^4}=27\)