(1/9)^x = (1/27)^22
(4/9)^x = (8/27)^6
Tìm X
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a) \(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(\Leftrightarrow\left(\frac{2}{3}\right)^{2x}=\left(\frac{2}{3}\right)^{18}\)
\(\Leftrightarrow2x=18\)
\(\Leftrightarrow x=9\)
b) \(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^{22}\)
\(\Leftrightarrow\left(\frac{1}{9}\right)^x=\left(\frac{1}{3}\right)^{66}\)
\(\Leftrightarrow x=66\)
\(\left(\dfrac{4}{9}\right)^{x+1}=\left(\dfrac{8}{27}\right)^6\)
\(\Leftrightarrow\left(\dfrac{2}{3}\right)^{2x+2}=\left(\dfrac{2}{3}\right)^{18}\)
\(\Leftrightarrow2x+2=18\Leftrightarrow2x=16\Leftrightarrow x=8\)
Trả lời :
\(\left(\frac{4}{9}\right)^{x+1}=\left(\frac{8}{27}\right)^6\)
\(\Rightarrow\left[\left(\frac{2}{3}\right)^2\right]^{x+1}=\left[\left(\frac{2}{3}\right)^3\right]^6\)
\(\Rightarrow\left(\frac{2}{3}\right)^{2x+2}=\left(\frac{2}{3}\right)^{18}\)
\(\Rightarrow2x+2=18\)
\(\Rightarrow2x=16\)
\(\Rightarrow x=8\)
\(\left(\frac{4}{9}\right)^{x+1}=\left(\frac{8}{27}\right)^6=>\left[\left(\frac{2}{3}\right)^2\right]^{x+1}=\left[\left(\frac{2}{3}\right)^3\right]^6\)
\(\left(\frac{2}{3}\right)^{2.\left(x+1\right)}=\left(\frac{2}{3}\right)^{18}=>2.\left(x+1\right)=18\)
\(\left(x+1\right)=18:2=>\left(x+1\right)=9\)
\(x=9-1=>x=8\)
vậy \(x=8\)
Bài 2:
Sau 2 giờ con ốc sên bò được:
1/5+1/6=11/30(cây cột)
Sau 2 giờ thì con ốc sên còn phải bò:
1-11/30=19/30(cây cột)
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
1).( 27,56 x 35 ) + ( 27,56 x 67 ) - ( 27,56 x 2)
= (964 + 1846,52) - 55,12
=2810,52 - 55,12
= 2755,4
2).( 4x 35 ) x ( 25 x 5 ) x 2
= ( 140 x 125 ) x2
= 17500 x 2
=35000
4). 3/10
5). 1188
6). 61/6
a) \(\left(\frac{1}{9}\right)^x=\left(\frac{1}{27}\right)^{22}\)
\(\left[\left(\frac{1}{3}\right)^2\right]^x=\left[\left(\frac{1}{3}\right)^3\right]^{22}\)
\(\left(\frac{1}{3}\right)^{2\cdot x}=\left(\frac{1}{3}\right)^{66}\)
\(\Rightarrow2\cdot x=66\)
\(x=66\div2\)
\(x=33\)
Vậy x = 33
b) \(\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(\left[\left(\frac{2}{3}\right)^2\right]^x=\left[\left(\frac{2}{3}^3\right)\right]^6\)
\(\left(\frac{2}{3}\right)^{2\cdot x}=\left(\frac{2}{3}\right)^{18}\)
\(\Rightarrow2\cdot x=18\)
\(x=18\div2\)
\(x=9\)
Vậy x = 9