(-2):1,5^2-(-0,75).2/3
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0,75 *95+1,5*2+0,75
=0,75 *95+1,5*2+0,75*1
=0.75*(95+1)+3
=0.75*96+3
=72+3
=75
Vì |a| = 1,5 nên a = 1,5 hoặc a = -1,5
Với a = 1,5; b = -0,75. Ta có:
M = 1,5 + 2.1,5( - 0,75) – (-0,75)
= 1,5 + ( -2,25) + 0,75
= (1,5 + 0,75) + (-2,25)
= 2,25 + (-2,25) = 0
N = 1,5 : 2 -2 : ( -0,75)
P = (-2) : (1,5)2 - (-0,75).(2/3)
Với a = -1,5; b = -0,75 ta có:
M = - 1,5 + 2.(-1,5) ( - 0,75) – (-0,75)
= - 1,5 + ( 2,25) + 0,75
= (2,25+ 0,75) - 1,5
= 3 – 1,5 = 1,5
N = - 1,5 : 2 - 2 : ( -0,75)
P = (-2) : (-1,5)2 — (-0,75).(2/3)
\(P=\dfrac{\left(-2\right)}{1.5^2}+0.75\cdot\dfrac{2}{3}=\dfrac{-8}{9}+\dfrac{1}{2}=\dfrac{-16+9}{18}=\dfrac{-7}{18}\)
Do |a| = 1,5 => \(\left[\begin{array}{nghiempt}a=1,5\\a=-1,5\end{array}\right.\) => a2 = (1,5)2 = \(\frac{9}{4}\)
Thay a = \(\frac{9}{4}\); b = -0,75, t có: \(P=\left(-2\right):\frac{9}{4}-\left(-0,75\right).\frac{2}{3}\)
\(P=\left(-2\right).\frac{4}{9}-\frac{-3}{4}.\frac{2}{3}\)
\(P=\frac{-8}{9}-\frac{-1}{2}\)
\(P=\frac{-8}{9}+\frac{1}{2}\)
\(P=\frac{-16}{18}+\frac{9}{18}=\frac{-7}{18}\)
\(P=\dfrac{-2}{1.5^2}+\dfrac{3}{4}\cdot\dfrac{2}{3}=\dfrac{-8}{9}+\dfrac{1}{2}=\dfrac{-16+9}{18}=\dfrac{-7}{18}\)
a, \(\Leftrightarrow2x^2=72\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow x=\pm6\)
Vậy ...
\(b,\Leftrightarrow\dfrac{3}{5}x-0,75=2\dfrac{4}{5}.\dfrac{3}{7}=\dfrac{6}{5}\)
\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{6}{5}+0,75=\dfrac{39}{20}\)
\(\Leftrightarrow x=\dfrac{39}{20}:\dfrac{3}{5}=\dfrac{13}{4}\)
Vậy ...
\(c,\Leftrightarrow2x=1\dfrac{5}{6}.\dfrac{6}{11}-\dfrac{3}{10}=\dfrac{7}{10}\)
\(\Leftrightarrow x=\dfrac{7}{10}:2=\dfrac{7}{20}\)
Vậy ...
\(d,\Leftrightarrow\dfrac{1}{x-7\dfrac{1}{3}}=1.5:2\dfrac{1}{4}=\dfrac{2}{3}\)
\(\Leftrightarrow x-7\dfrac{1}{3}=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{3}{2}+7\dfrac{1}{3}=\dfrac{53}{6}\)
Vậy ...
a) 2x2 - 72 = 0
\(\Rightarrow\) 2x2 = 72
\(\Rightarrow\) x2 = 36 = 62 = (- 6)2
\(\Rightarrow\) x = 6 hoặc x = - 6
Vậy x = 6 hoặc x = - 6
b) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(2\dfrac{4}{5}\)
\(\Rightarrow\) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(\dfrac{14}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x - \(\dfrac{3}{4}\) = \(\dfrac{6}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x = \(\dfrac{39}{20}\)
\(\Rightarrow\) x = \(\dfrac{13}{4}\)
Vậy x = \(\dfrac{13}{4}\)