Tìm x
x + 9.x + 7.x + 5.x = 2244
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
TM
3
C
17 tháng 4 2022
x*3,4=15,3
x = 15,3 : 3,4
x = 4,5
7,5:x=0,24
x = 7,5 : 0,24
x = 31,25
5/6:x=7/8
x = 5/6 : 7/8
x = 20/21
2/3*x=5/9
x = 5/9 : 2/3
x = 5/6
VQ
17 tháng 4 2022
Xx3,4=15,3
X = 15,3 : 3,4
X =4.5
7,5:x=0,24
x=7,5 : 0,24
x= 31.25
5/6:x=7/8
x=5/6 : 7/8
x= 20/21
2/3xX=5/9
X= 5/9 : 2/3
X= 5/6
HK
2
C
20 tháng 3 2023
`x xx 6/7=5/14`
`=>x=5/14:6/7`
`=>x=5/14xx7/6`
`=>x=35/84`
`=>x=5/12`
Vậy `x=5/12`
__
`x:2/3=4/9`
`=>x=4/9xx2/3`
`=>x=8/27`
Vậy `x=8/27`
__
`x-1/4=3/2`
`=>x=3/2+1/4`
`=>x=6/4+1/4`
`=>x=7/4`
Vậy `x=7/4`
__
`x+4/5=8/9`
`=>x=8/9-4/5`
`=>x=40/45-36/45`
`=>x=4/45`
Vậy `x=4/45`
T
20 tháng 3 2023
\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)
\(x\) \(=\dfrac{5}{14}:\dfrac{6}{7}\)
\(x\) \(=\dfrac{5}{12}\)
\(x:\dfrac{2}{3}=\dfrac{4}{9}\)
\(x\) \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)
\(x\) \(=\dfrac{8}{27}\)
\(x-\dfrac{1}{4}=\dfrac{3}{2}\)
\(x\) \(=\dfrac{3}{2}+\dfrac{1}{4}\)
\(x\) \(=\dfrac{7}{4}\)
\(x+\dfrac{4}{5}=\dfrac{8}{9}\)
\(x\) \(=\dfrac{8}{9}-\dfrac{4}{5}\)
\(x\) \(=\dfrac{4}{45}\)
9 tháng 3 2022
Bài 1:
a: x/-2=-18/x
=>x2=36
=>x=6 hoặc x=-6
b: x/2+x/5=17/10
=>7/10x=17/10
hay x=17/7
T
5
TM
6 tháng 11 2018
x + 9x + 7x + 5x = 2244
<=> 1x + 9x + 7x + 5x = 2244
x ( 1 + 9 + 7 + 5 ) = 2244
22x = 2244
x = 2244 : 22
x = 1122
6 tháng 11 2018
x + 9x + 7x + 5x = 2244
<=> 22x = 2244
<=> x = 2244 : 22
=> x = 102
ML
2
16 tháng 6 2021
Giải:
\(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+...+\dfrac{1}{x.\left(x+2\right)}=\dfrac{16}{99}\)
\(\dfrac{1}{2}.\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{x.\left(x+2\right)}\right)=\dfrac{16}{99}\)
\(\dfrac{1}{2}.\left(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{x}-\dfrac{1}{x+2}\right)=\dfrac{16}{99}\)
\(\dfrac{1}{2}.\left(\dfrac{1}{3}-\dfrac{1}{x+2}\right)=\dfrac{16}{99}\)
\(\dfrac{1}{3}-\dfrac{1}{x+2}=\dfrac{16}{99}:\dfrac{1}{2}\)
\(\dfrac{1}{3}-\dfrac{1}{x+2}=\dfrac{32}{99}\)
\(\dfrac{1}{x+2}=\dfrac{1}{3}-\dfrac{32}{99}\)
\(\dfrac{1}{x+2}=\dfrac{1}{99}\)
\(\Rightarrow x+2=99\)
\(x=99-2\)
\(x=97\)
Chúc em học tốt!
16 tháng 6 2021
\(\dfrac{1}{3x5}+\dfrac{1}{5x7}+\dfrac{1}{7x9}+...+\dfrac{1}{x\left(x+2\right)}=\dfrac{16}{99}\)
\(=\dfrac{1}{2}\left(\dfrac{2}{3x5}+\dfrac{2}{5x7}+...+\dfrac{2}{x\left(x+2\right)}\right)=\dfrac{16}{99}\)
\(=\dfrac{2}{3x5}\)\(+\dfrac{2}{5x7}+...+\dfrac{2}{x\left(x+2\right)}=\dfrac{32}{99}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}+.....+\dfrac{1}{x}-\dfrac{1}{x+2}=\dfrac{32}{99}\)
\(=\dfrac{1}{3}-\dfrac{1}{x+2}=\dfrac{32}{99}=>x=97\)
27 tháng 10 2021
\(x+x\cdot3:\dfrac{2}{9}+x:\dfrac{2}{7}=252\)
\(\Leftrightarrow x+x\cdot3\cdot\dfrac{9}{2}+x\cdot\dfrac{7}{2}=252\)
\(\Leftrightarrow x\cdot18=252\)
hay x=14
PM
1
G
3 tháng 9 2020
a) \(547+389+453+211\)
\(=\left(547+453\right)+\left(389+211\right)\)
\(=1000+600\)
\(=1600\)
b) \(158+445+342+555\)
\(=\left(158+342\right)+\left(445+555\right)\)
\(=500+1000\)
\(=1500\)
c) \(24.3.5.10\)
\(=\left(24.5\right).\left(10.3\right)\)
\(=120.30\)
\(=3600\)
d) \(12.5.15.7\)
\(=\left(12.5\right).\left(15.7\right)\)
\(=60.105\)
\(=6300\)
e) \(1122.34+2244.83\)
\(=1122.2.17+2244.83\)
\(=2244.17+2244.83\)
\(=2244.\left(17+83\right)\)
\(=2244.100\)
\(=224400\)
f) \(8466.15+170.4233\)
\(=8466.15+85.2.4233\)
\(=8466.15+85.8466\)
\(=8466.\left(15+85\right)\)
\(=8466.100\)
\(=846600\)
x + 9x + 7x + 5x = 2244
x ( 1 + 9 + 7 + 5 ) = 2244
x . 22 = 2244
x = 2244 : 22
x = 102
x= 102