17.(x+2)=16.(x+5)
Tìm x
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Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16
7+x=-16
x=-16-7
x=-23
2) 2x – 35 = 15
2x=15+35
2x=50
x=50:2
x=25
3) 3x + 17 = 12
3x=12-17
3x=-5
x=-5/3
4) (2x – 5) + 17 = 6
2x-5=6-17
2x-5=-11
2x=-11+5
2x=-6
x=-6:2
x=-3
5) 10 – 2(4 – 3x) = -4
2(4-3x)=10-(-4)
2(4-3x)=14
4-3x=14:2
4-3x=7
3x=4-7
3x=-3
x=-3:3
x=-1
6) - 12 + 3(-x + 7) = -18
3(-x+7)=-18-(-12)
3(x+7)=-6
x+7=-6:3
x+7=-2
x=-2-7
x=-9
d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)
\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)
hay \(x=\dfrac{25}{372}\)
Vậy: \(x=\dfrac{25}{372}\)
e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)
f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)
\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)
\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)
\(\Leftrightarrow3x=\dfrac{1}{9}\)
hay \(x=\dfrac{1}{27}\)
g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)
\(\Leftrightarrow\dfrac{4}{3}x=2\)
hay \(x=\dfrac{3}{2}\)
Vậy: \(x=\dfrac{3}{2}\)
h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)
Vậy ...
i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)
Vậy ...
A) x + 4 = -16
x = -16 - 4
x = -20
Vậy x = -20
b) 12- ( x - 5 ) =5.4
12 -x -5 = 20
x = 7 - 20
x = -13
Vậy x= -13
c) (-2)x - ( x - 17 ) = 34 - ( -x + 25 )
( -2 )x - x + 17 = 34 + x - 25
-3x + 17 = 11 + x
-3x - x = 11 - 17
-4x = -6
x = 1,5
Vậy x = 1,5
d) 17x - ( -16x - 37 ) = 2x + 43
17x + 16x - 2x = 43 -37
30x = 6
x = 0,2
Vậy x = 0,2
a) -16 + 23 + x = -16
=> 7 + x = -16
=> x = -16 - 7
=> x = -23
b) 3x + 17 = 12
=> 3x = 12 - 17
=> 3x = -5
=> x = -5/3
vì x là số nguyên => x ko có gtri thõa mãn đề bài
c) (2x - 5) + 17 = 16
=> 2x - 5 = 16 - 17
=> 2x - 5 = -1
=> 2x = -1 + 5
=> 2x = 4
=> x = 4 : 2
=> x = 2
\(-16+23+x=-16\)
\(\Rightarrow x=-16-23+16\)
\(\Rightarrow x=-23\)
\(3x+17=12\)
\(3x=-5\)
\(x=-\frac{5}{3}\)
\(24:\left(3x-2\right)=-3\)
\(\Rightarrow3x-2=-8\)
\(3x=-6\)
\(x=-2\)
\(\left(2x-5\right)+17=16\)
\(2x=16-17+5\)
\(x=2\)
\(-6< x< 3\)
\(\Rightarrow x\in\left\{-5;-4;-3;-2;-1;0;1;2\right\}\)
"Tự tính tổng "
a) x = 4
b) x = 3
c) x = 2
d) x = 1
e) x = 3
f) x = 2
g) x = 4
h) x = 3
\(17\cdot\left(x+2\right)=16\cdot\left(x+5\right)\)
\(17x+34=16x+80\)
\(x=80-34=46\)
Vậy \(x=46\)