\(\left(1-\frac{3}{5}\right)^2+|\frac{-7}{23}|+\left(-\frac{4}{25}\right)\)
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\(A=\left(4+\frac{1}{5}\right).\frac{19}{8}+\left(2+\frac{5}{8}\right).\frac{21}{5}\) =\(\frac{21}{5}.\frac{19}{8}+\frac{21}{8}.\frac{21}{5}\) =\(\frac{21}{5}.\left(\frac{19}{8}+\frac{21}{8}\right)\) = \(\frac{21}{5}.5\) =21 \(B=\frac{25}{2}.\left(3+\frac{2}{7}\right)-\frac{23}{7}.\left(5+\frac{1}{2}\right)\) =\(\frac{25}{2}.\frac{23}{7}-\frac{23}{7}.\frac{11}{2}\) =\(\frac{23}{7}.\left(\frac{25}{2}-\frac{11}{2}\right)\) =\(\frac{23}{7}.7=23\)
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a) \(\frac{17}{9}-\frac{17}{9}:\left(\frac{7}{3}+\frac{1}{2}\right)\)
= \(\frac{17}{9}-\frac{17}{9}:\frac{17}{6}\)
= \(\frac{17}{9}-\frac{2}{3}\)
= \(\frac{11}{9}\)
b) \(\frac{4}{3}.\frac{2}{5}-\frac{3}{4}.\frac{2}{5}\)
= \(\frac{2}{5}.\left(\frac{4}{3}-\frac{3}{4}\right)\)
= \(\frac{2}{5}.\frac{7}{12}\)
= \(\frac{7}{30}\)
Mình lười làm quá, hay mình nói kết quả cho bn thôi nha
c) -6
d) 3
e) 3
g) 12
h) \(\frac{23}{18}\)
i) \(\frac{-69}{20}\)
k) \(\frac{-1}{2}\)
l) \(\frac{49}{5}\)
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Bài 1:
d)
= \(\frac{-5}{9}\left(\frac{6}{13}+\frac{7}{13}\right)+\frac{5}{23}.\frac{7}{9}\)
= \(\frac{-5}{9}.1+\frac{35}{207}\)
= \(\frac{-80}{207}\)
Bài 2:
a) 20%x + 0,4x = 4,5
x( 20% + 0,4 ) = 4,5
x. 0,6 = 4,5
x = 4,5 : 0,6
x = 7,5
\(\left(1-\frac{3}{5}\right)^2+\left|\frac{-7}{23}\right|+\left(-\frac{4}{25}\right)\)\(\)
\(=\left(\frac{2}{5}\right)^2+\frac{7}{23}-\frac{4}{25}\)
\(=\frac{4}{25}-\frac{4}{25}+\frac{7}{23}\)
\(=\frac{7}{23}\)
\(\left(1-\frac{3}{5}\right)^2+\left|-\frac{7}{23}\right|+\left(-\frac{4}{25}\right)\)
\(=\left(\frac{5}{3}-\frac{3}{5}\right)^2+\frac{7}{23}-\frac{4}{25}\)
\(=\left(\frac{2}{5}\right)^2-\frac{4}{25}+\frac{7}{23}\)
\(=\frac{4}{25}-\frac{4}{25}+\frac{7}{23}\)
\(=\frac{7}{23}\)