( x - 55 ) x 17 = 3
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45 + 6 x 17 + 55 + 2 x 3 x 83
= 45 + 102 + 55 + 6 x 38
= 45 + 102 + 55 + 228
= 147 + 55 + 228
= 202 + 228
= 430
Lời giải:
$(-55).(-17)-55.(-2+17)=(-55)(-17)-55.15=(-55)(-17)+(-55).15$
$=(-55)(-17+15)=(-55).(-2)=55.2=110$
Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
(12000+X):376=X
12000+X=376 x X
12000=376 x X - X
12000=375 x X
X=12000:375= 32
a.
\(3-\left(17-x\right)=289-\left(36+289\right)\)
\(3-17+x=289-36-289\)
\(x=\left(289-289\right)+\left(-36-3+17\right)\)
\(x=-22\)
b.
\(x-73=\left(-35\right)+\left|-55\right|\)
\(x-73=-35+55\)
\(x=-35+55+73\)
\(x=93\)
c.
\(\left|x\right|-3=2\)
\(\left|x\right|=3+2\)
\(\left|x\right|=5\)
\(x=\pm5\)
Vậy x = 5 hoặc x = -5
d.
\(\left|x+1\right|=5\)
\(x+1=\pm5\)
TH1:
\(x+1=5\)
\(x=5-1\)
\(x=4\)
TH2:
\(x+1=-5\)
\(x=-5-1\)
\(x=-6\)
Vậy x = 4 hoặc x = -6
a, \(3-17+x=289-36-289\)
\(\Rightarrow x-14=-36\)
\(\Rightarrow x=-22\)
\(b,x-73=\left(-35\right)+\left|-55\right|\)
\(\Rightarrow x-73=\left(-35\right)+55\)
\(\Rightarrow x-73=20\)
\(\Rightarrow x=93\)
\(c,\left|x\right|-3=2\)
\(\Rightarrow\left|x\right|=5\)
\(\Rightarrow x=\pm5\)
\(d,\left|x+1\right|=5\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}x+1=5\\x+1=-5\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=4\\x=-6\end{array}\right.\)
x-55=3x17
x-55=51
x=51+55
x=106
tk nha
(x-55). 17=3
\(\Rightarrow x-55=\frac{3}{17}\)
\(\Rightarrow x=\frac{3}{17}+55\)
\(\Rightarrow x=\frac{3+935}{17}\)
\(\Rightarrow x=\frac{938}{17}\)