x-12 trên 35 =4/7
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*\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left[\frac{1}{14}+\frac{1}{7}-\left(-\frac{3}{35}\right)\right].\frac{4}{3}}=\frac{\left(\frac{18}{60}-\frac{16}{60}-\frac{21}{60}\right).\frac{5}{19}}{\left(\frac{5}{70}+\frac{10}{70}+\frac{6}{70}\right).\frac{4}{3}}=\frac{\frac{-19}{60}.\frac{5}{19}}{\frac{21}{70}.\frac{4}{3}}=\frac{\frac{-1}{12}}{\frac{14}{35}}=-\frac{1}{12}.\frac{35}{14}=\frac{-35}{168}\)
*\(\frac{\left(1+2+3+...+100\right).\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(6,3.12-21.3,6\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
=\(\frac{\left(1+2+3+...+100\right)\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(\frac{63}{10}.12-21.\frac{18}{5}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
=\(\frac{\left(1+2+3+...+100\right)\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(\frac{378}{5}-\frac{378}{5}\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
=\(\frac{\left(1+2+3+...+100\right)\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).0}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}=0\)
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\(4+\dfrac{x}{15}=\dfrac{3}{5}\)
⇒ \(\dfrac{x}{15}=\dfrac{3}{5}-4=\dfrac{-17}{5}=\dfrac{-51}{15}\)
Vậy x = -51
\(x-\dfrac{12}{35}=\dfrac{4}{7}\)
⇒ \(x=\dfrac{4}{7}+\dfrac{12}{35}=\dfrac{32}{35}\)
Vậy x = \(\dfrac{32}{35}\)
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Bài 1:
a: -8/12<0<-3/-4
b: -56/24<0<7/3
c: 4/25<1<15/13
=>-4/25>-15/13
Bài 2:
a: =-60/45=-4/3
b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6
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`\text {12 ngày 8 giờ - 2 ngày 15 giờ x 3 = 12 ngày 8 giờ - 7 ngày 21 giờ = 4 ngày 11 giờ}`
`11/12 \times 5/6 \times 4/3=55/72 \times 43=55/54`
`5/7+3/8 \div 9/2=5/7+1/12=67/84`
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a.245 x ( 327-18-9) = 245 x 300 = 73500
b. (462 - 62) x 4 = 1600
c. 900 : 9 = 100
d. (12+20) : 4 = 8
245x327-245x18-9x245 462 x 4 - 62 x 4
=245x(327-18-9) = ( 462 - 62) x 4
=245x300 = 400 x 4
=73500 = 1600
35 : 7 - 21 : 7 ( 25 x 36 ) : 9
= ( 35 - 21) : 7 = 900 : 9
= 14 : 7 = 100
= 2
12 : 4 + 20 : 4
= ( 12 + 20 ) : 4
= 32 : 4
= 8
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Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
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51/60 x 12/17 : 3/10= 51/60 x 12/17 x 10/3 = 6120/3060 = 2
5/12 : 7/4 - 25/18 : 35/6 = 5/12 x 4/7 - 25/18 x 6/35 = 5/21 - 5/21 = 0
x-12/35=4/7
x=4/7+12/35
x=32/35
vậy x=32/25
---> \(\frac{x-12}{35}=\frac{4}{7}\)
---> \(\frac{x-12}{35}=\frac{20}{35}\)
---> x - 12 = 20
---> x = 32
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