Tim x (x+3)^2-(x-4)(x+8)=1
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\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)
a: =>6/x=3/8
hay x=16
b: =>x/27=1/9
nên x=3
c: =>4/x=4/3
nên x=3
d: =>3/x-5=-4/x+2
=>3x+2=-4x+20
=>7x=18
hay x=18/7
Ta có : ( x+1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) = 30
( x + x + x +x +x ) + ( 1 + 2 + 3 + 4 + 5 ) = 30
x * 5 + 15 = 30
x * 5 = 30 - 15
x * 5 = 15
x = 15 : 5
x = 3
Vậy x = 3
Duyệt đi , chúc bạn học giỏi
(x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) = 4 + 5 + 6 + 7 + 8
x + 1 + x + 2 + x + 3 + x + 4 + x + 5 = 30
\(x\)x 5 + 15 = 30
\(x\)x 5 = 30 - 15 = 15
x = 15 : 5 = 3
A
\(\frac{3}{5}\div\frac{4}{5}+\frac{1}{2}\times\frac{2}{3}\)
\(=\frac{3}{4}+\frac{1}{3}\)
\(=\frac{13}{12}\)
B
\(\frac{5}{4}\times x=\frac{3}{8}+\frac{1}{4}\)
\(\frac{5}{4}\times x =\frac{5}{8}\)
\(x=\frac{5}{8}\div\frac{5}{4}\)
\(x=\frac{4}{8}=\frac{1}{2}\)
\(x+\dfrac{3}{4}=\dfrac{1}{2}+\dfrac{9}{8}\\ x+\dfrac{3}{4}=\dfrac{4}{8}+\dfrac{9}{8}\\ x+\dfrac{3}{4}=\dfrac{13}{8}\\ x=\dfrac{13}{8}-\dfrac{3}{4}\\ x=\dfrac{13}{8}-\dfrac{6}{8}\\ x=\dfrac{7}{8}\)
x + 3/4 = 1/2 + 9/8
x + 3/4 = 13/8
x = 13/8 -3/4
x = 7/8
x(3-x)=0
Th1: x=0
Th2: 3-x=0 => x=3
Vậy x=0 và x=3
(x+2)(4x-8)=0
Th1: x+2= 0 => x=-2
Th2: 4x-8 =0 => 4x =8
x= 2
Vậy x= +- 2 (cộng trừ 2 nhé)
(x+1)+(x+2)+(x+3)+....+(x+199)=5750
199x +(1+2+3+...199) =5750
199x+ {(199+1)* [(199-1)+1] : 2} =5750
199x + 19900= 5750
199x = -14150
x= -14150/199
12x/6 + 4x/6 - 3x/6 = 3/8 - 1/4 - 1/6
13x/6 = (9 - 6 - 4)/24 = -1/24
--> x = -1/52
\(\dfrac{3}{x-5}=\dfrac{-4}{x+2}\)=>3.(x+2)=(x-5).(-4)
=> 3.2+3.x=x.(-4)-(-4).5
=>6+3.x=x.(-4)-(-20)
=>3.x-x.(-4)=20-6
=>3.x-x.(-4)=14
=>x.(3+4)=14(vì 3-(-4)=3+4)
=>x.7=14
=>x=14:7
=>x=2
ta có:x/2+3x/4+x/2+x/4=8
=>(x/2+x/2)+(3x/4+x/4)=8
=>x+x=8
=>2x=8
=>x=4
kích mình nhé
\(\left(x+3\right)^2-\left(x-4\right)\left(x+8\right)=1\)
\(\Leftrightarrow x^2+6x+9-x^2+8x-4x-32=1\)
\(\Leftrightarrow x^2+6x+9-\left(x^2+4x-32\right)=1\)
\(\Leftrightarrow x^2+6x+9-x^2-4x+32=1\)
\(\Leftrightarrow2x+41=1\)
\(\Leftrightarrow2x=-40\Leftrightarrow x=-20\)
2x+41=1
=> 2X = 1 - 41 = 40
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