tìm x,biết:
7.23x+1-12=22.52
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a, 10 x + 2 2 . 5 = 10 2
10x = 100–20
10x = 80
x = 8
b, 5 2 + 15 - x = 30
15–x = 5
x = 10
c, 2 2 . 5 2 - 25 + x = 40
100–(25+x) = 40
25+x = 60
x = 35
d, 7 2 x - 6 2 x = 13 . 2 3 - 26
49x–36x = 104–26
13x = 78
x = 6
a) 27.75 + 25.27 - 150.2023⁰
= 27.(75 + 25) - 150.1
= 27.100 - 150
= 2700 - 150
= 2550
b) Sửa đề:
3ˣ + 3ˣ⁺¹ + 16.4 = 2².5²
3ˣ.(1 + 3) + 64 = 4.25
3ˣ.4 + 64 = 100
3ˣ.4 = 100 - 64
3ˣ.4 = 36
3ˣ = 36 : 4
3ˣ = 9
3ˣ = 3²
x = 2
a, \(15:\left(x+2\right)=3\Leftrightarrow x+2=3\Leftrightarrow x=1\)
b, \(20:\left(x+1\right)=2\Leftrightarrow x+1=10\Leftrightarrow x=9\)
c, \(240:\left(x-5\right)=2^2.5^2-20=80\Leftrightarrow x-5=3\Leftrightarrow x=8\)
d, \(96-3\left(x+1\right)=42\Leftrightarrow3\left(x+1\right)=54\Leftrightarrow x+1=18\Leftrightarrow x=17\)
a) 15 : (x + 2) = 3
x + 2 = 15 : 3
x + 2 = 5
x = 5 – 2 = 3
b) 20 : (1 + x) = 2
1 + x = 20 : 2
1 + x = 10
x = 10 – 1 = 9
c) 240 : (x – 5) = 22.52 – 20
240 : (x – 5) = 4.25 – 20
240 : (x - 5) = 100 – 20
240 : (x - 5) = 80
x – 5 = 240 : 80
x – 5 = 3
x = 3 + 5 = 8
d) 96 - 3(x + 1) = 42
3(x + 1) = 96 – 42
3(x + 1) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 – 1
x = 17
`240:(x–5)=22xx52–20`
`240:(x–5)=1144-20`
`240:(x-5)=1124`
`x-5=240:1124`
`x-5=60/281`
`x=60/281 + 5`
`x=1465/281`
240:(x - 5)=1144 - 20
240:(x - 5)=1124
x - 5 =240:1124
x - 5 = 60/281
x = 60/281 + 1405/281
x = 1465/281
\(240:\left(x-5\right)=22\cdot52-20\)
\(\Leftrightarrow240:\left(x-5\right)=1124\)
\(\Leftrightarrow x-5=\dfrac{60}{281}\)
hay \(x=\dfrac{1465}{281}\)
\(\Leftrightarrow240:\left(x-5\right)=1124\\ \Leftrightarrow x-5=\dfrac{60}{281}\Leftrightarrow x=\dfrac{1465}{281}\)
1.8100
2. 34 x 18 + 18 x 66
= 18 x ( 34 + 66)
= 18 x 100 = 1800
3. X × ( 8 + 12) = 160 + 20 × 12
= X x 20 = 160 + 240
= X x 20 = 400
X = 400 : 20 = 20
4. X x 12 - X x 2 = 2020
(12 - 2) x X = 2020
10 x X = 2020
X = 2020 : 10 = 202
a: =321-21*[(2*27+16:32)-52]
=321-21*[2+0,5]
=321-21*2,5=268,5
b: \(=\dfrac{160}{17+\left[9\cdot5\left(14+8\right)\right]}\)
\(=\dfrac{160}{17+45\cdot22}=\dfrac{160}{1007}\)
c: =100*9:3^2=100
d: =2*27+143:(36-25)
=54+143:11
=54+13=67
\(7\cdot2^{3x+1}-12=2^2\cdot5^2\)
\(\Rightarrow7\cdot2^{3x+1}-12=100\)
\(\Rightarrow7\cdot2^{3x+1}=100+12=112\)
\(\Rightarrow2^{3x+1}=\dfrac{112}{7}=16=2^4\)
\(\Rightarrow3x+1=4\Rightarrow3x=3\Rightarrow x=1\)
Vậy x = 1