7 1/5 = m/5 +27/5
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O
0
15 tháng 7 2023
`1 5/27 + 7 /23 + 1/2 - 5/27 + 16/23`
` = 32/27 + 7/23 + 1/2 - 5/27 + 16/23 `
`= (32/27 - 5/27 ) + (7/23 + 16/23 ) + 1/2 `
`= 27/27 + 23/23 + 1/2 `
`= 1 + 1 + 1/2 `
`= 5/2`
` 6 1/5 - ( 2/3 . 9/10 - 7/5 )`
` = 31/5 - 2/3 . 9/10 + 7/5 `
`= ( 31/5 + 7/5 ) - ( 2/3 . 9/10 ) `
`= 38/5 - 3/5 `
`= 35/5`
`= 7`
`@ animephamdanhv.`
DQ
1
KN
17 tháng 8 2020
\(A=\frac{2^{30}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}\)
\(=\frac{2^3\left(2^{27}.5^7+2^{10}.5^{27}\right)}{2^{27}.5^7+2^{10}.5^{27}}\)
\(=2^3=8\)
VM
1 tháng 10 2019
\(A=\frac{2^{30}.5^7+2^{13}.5^{27}}{2^{27}.5^7+2^{10}.5^{27}}\)
\(A=2^3.1+2^3.1\)
\(A=2^3.\left(1+1\right)\)
\(A=2^3.2\)
\(A=2^4\)
\(A=16.\)
b) Câu này bạn viết đề như thế thì không ai hiểu được đâu nhé.
Chúc bạn học tốt!
23 tháng 6 2022
a: \(=\dfrac{2}{3}+\dfrac{19}{35}=\dfrac{70+57}{105}=\dfrac{127}{105}\)
b: \(=\dfrac{2}{7}+\dfrac{2}{5}=\dfrac{24}{35}\)
c: \(=\dfrac{7}{12}-\dfrac{14}{2}=\dfrac{7-84}{12}=\dfrac{-77}{12}\)
d: \(=\dfrac{-15}{60}-\dfrac{1}{8}=-\dfrac{3}{8}\)
e: \(=-\dfrac{12}{72}+\dfrac{1}{18}=\dfrac{-3}{18}+\dfrac{1}{18}=\dfrac{-2}{18}=\dfrac{-1}{9}\)
18 tháng 7 2017
a,x.3\(\dfrac{1}{4}\)+(\(\dfrac{-7}{6}\)).x-1\(\dfrac{2}{3}\)=\(\dfrac{5}{12}\)
\(\Leftrightarrow\)\(\dfrac{13}{4}\)x+(\(\dfrac{-7}{6}\))x-\(\dfrac{5}{3}\)=\(\dfrac{5}{12}\)
\(\Leftrightarrow\)\(\dfrac{13}{4}\)x+(\(\dfrac{-7}{6}\))x=\(\dfrac{25}{12}\)
\(\Leftrightarrow\)\(\dfrac{25}{12}\)x=\(\dfrac{25}{12}\)
\(\Leftrightarrow\)x=1
Vậy x=1
b,\(\dfrac{2}{5}\)+\(\dfrac{3}{5}\).(3x-3,7)=\(\dfrac{-53}{10}\)
\(\Leftrightarrow\)\(\dfrac{3}{5}\).(3x-3,7)=\(\dfrac{-53}{10}\)-\(\dfrac{2}{5}\)
\(\Leftrightarrow\)\(\dfrac{9}{5}\)x-\(\dfrac{111}{50}\)=\(\dfrac{-57}{10}\)
\(\Leftrightarrow\)\(\dfrac{9}{5}\)x=\(\dfrac{-87}{25}\)
\(\Leftrightarrow\)x=\(\dfrac{-29}{15}\)
Vậy x=\(\dfrac{-29}{15}\)
c,\(\dfrac{7}{9}\):(2+\(\dfrac{3}{4}\)x)+\(\dfrac{5}{9}\)=\(\dfrac{23}{27}\)
\(\Leftrightarrow\)\(\dfrac{7}{9}\):(2+\(\dfrac{3}{4}\)x)=\(\dfrac{8}{27}\)
\(\Leftrightarrow\)\(\dfrac{7}{18}\)+\(\dfrac{28}{27}\)x=\(\dfrac{8}{27}\)
\(\Leftrightarrow\)\(\dfrac{28}{27}\)x=\(\dfrac{-5}{54}\)
\(\Leftrightarrow\)x=\(\dfrac{-5}{56}\)
Vậy x=\(\dfrac{-5}{56}\)