X-3=(19+24+X):3
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3/11x7/19+3/11x17/19-3/11x24/19
=3/11x(7/19+17/19-24/19)
=3/11x0
=0
Bài làm
\(\frac{3}{11}\times\frac{7}{19}+\frac{3}{11}\times\frac{17}{19}-\frac{3}{11}\times\frac{24}{19}\)
\(=\frac{3}{11}\times\left(\frac{7}{19}+\frac{17}{19}-\frac{24}{19}\right)\)
\(=\frac{3}{11}\times\frac{0}{19}\)
\(=\frac{3}{11}\times0\)
\(=0\)
# Học tốt #
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Câu 1 : 65.(-19)+19.(-24)= (-65).19+19.(-24)=19.[(-65)+(-24)]=19.(-89)=-1691
Câu 2:a) 7x.(2+x)-7x(x+3)=14
=>7x.(2+x-x-3)=14
=>7x.(-1)=14
=>(-7).x=14
=>x=14:(-7)
=>x=-2
Vậy x=-2
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Mình làm lun nhé
X x 5 -19 + X x 3 + 24 =125(PHá ngoặc)
X x(5+3) +24-19=125
X x 8 +5=125
X x 8 =125 -5
X x 8 =120
\(5x-19+3x+24=125\)
\(5x+3x=125+19-24\)
\(8x=120\)
\(x=120:8\)
\(x=15\)
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( 5 x − 19 ) + ( 3 x + 24 ) = 125
. 5 x − 19 + 3 x + 24 = 125
8 x + 5 = 125
8 x = 120
x = 15
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\(\left(x\times5-19\right)+\left(x\times3-24\right)=125\)
\(x\times\left(5+3\right)-\left(19+24\right)=125\)
\(x\times8-43=125\)
\(x\times8=125-43\)
\(x\times8=82\)
\(x=\frac{82}{8}=\frac{41}{4}\)
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