288 - (88 - 5^4) - (4x^4 -200) = 416
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\(288-\left(88+5^4\right)-\left(4x^4-200\right)=416\)
\(\Leftrightarrow288-88-625-4x^4+200=416\)
\(\Leftrightarrow-4x^4-225=416\)
\(\Leftrightarrow-4x^4=641\)(vô lý)
288 - (88 + 54) - (4x4 - 200) = 416
<=> 288 - 88 - 625 - 4x4 + 200 = 416
<=> 288 - 88 - 625 - 416 + 200 = 4x4
<=> -641 = 4x4
<=> x4 = -160,25
<=> x = \(-\sqrt[4]{160,25}\) = -3,557947288 \(\approx\) -3,56
1.a) 4.(12+88) = 4.100=400
b)72- 6 .[2.8:8 ]=72-6.[16:8]=72-6 .2= 49-12=37 ( tui ko chắc lắm )
2.a) x=26-11=15
b) (4x-15)3=53
4x-15=5
4x= 5+15
4x=20
vậy x = 20
Bài 2:
a: Ta có: x+11=26
nên x=15
b: Ta có: \(\left(4x-15\right)^3=125\)
\(\Leftrightarrow4x-15=5\)
hay x=5
(2x-1)+(4x-2)+(8x-4)+...+(400x-200)= 5+10+...+1000
<=> (2x-1) + 2 (2x-1) + 4 (2x-1) + ...+ 200 (2x-1) = 5.(1 + 2 + ...+ 200)
<=> (2x-1) (1 + 2 + 4 +... + 200) = 5.(1 + 2 + ...+ 200)
<=> 2x - 1 = 5
=> 2x = 5 + 1 = 6
=> x = 3
a) x – 32 : 16 = 48 ó x – 2 = 48 ó x = 48 + 2 ó x = 50
b) 88 – 3.(7+x) = 64 ó 3.(7+x) = 88 – 64 ó 7 + x = 24:3 ó x = 8 – 7 ó x = 1
c) (5+4x) : 3 – 121 : 11 = 4 ó (5+4x) : 3 – 11 = 4 ó (5+4x) : 3 = 4 + 11 ó 5+4x = 15.3 ó 4x = 45 – 5 ó 4x = 40 ó x = 10
d) 15 – 2(3x+1) = 11.13 – 130 ó 15 – 2(3x+1) = 143 – 130 ó 15 – 2(3x+1) = 13
ó 2(3x+1) = 15 – 13 ó 3x + 1 = 2:2 ó 3x = 1 – 1 ó 3x = 0 ó x = 0
\(288-\left(88+5^4\right)-\left(4x^4-200\right)=416\)
\(\Leftrightarrow288-88-625-4x^4+200=416\)
\(\Leftrightarrow-4x^4-225=416\)
\(\Leftrightarrow-4x^4=641\)(vô lý)