-5/3-(5/12-3/4)<X<11/6-(1/3+1/4)
GIÚP MK VỚI MAI MK PHẢI NỘP RÙI AI NHANH MK TICK CHO NHÉ
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
21 tháng 11 2024
\(\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{2}{4}\)
= \(\dfrac{24}{60}\) + \(\dfrac{40}{60}\) + \(\dfrac{30}{60}\)
= \(\dfrac{64}{60}\) + \(\dfrac{30}{60}\)
= \(\dfrac{47}{30}\)
\(\dfrac{2}{6}+\dfrac{3}{12}\)
= \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\)
= \(\dfrac{7}{12}\)
\(\dfrac{5}{6}\) + \(\dfrac{1}{3}\)
= \(\dfrac{5}{6}\) + \(\dfrac{2}{6}\)
= \(\dfrac{7}{6}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
21 tháng 11 2024
\(\dfrac{1}{3}\) + \(\dfrac{5}{12}\) + \(\dfrac{5}{6}\)
= \(\dfrac{4}{12}\) + \(\dfrac{5}{12}\) + \(\dfrac{10}{12}\)
= \(\dfrac{9}{12}\) + \(\dfrac{10}{12}\)
= \(\dfrac{19}{12}\)
\(\dfrac{5}{8}\) + \(\dfrac{4}{7}\)
= \(\dfrac{35}{56}\) + \(\dfrac{32}{56}\)
= \(\dfrac{67}{56}\)
\(\dfrac{7}{3}\) + \(\dfrac{8}{7}\)
= \(\dfrac{49}{21}\) + \(\dfrac{24}{21}\)
= \(\dfrac{73}{21}\)
\(\dfrac{1}{5}+\dfrac{5}{35}\)
= \(\dfrac{7}{35}\) + \(\dfrac{5}{35}\)
= \(\dfrac{12}{35}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
10 tháng 7 2024
\(\dfrac{4}{5}\) : (\(\dfrac{4}{5}\) .- \(\dfrac{5}{4}\)) : (\(\dfrac{16}{25}\) - \(\dfrac{1}{5}\))
= \(\dfrac{4}{5}\) : (-1) : (\(\dfrac{16}{25}\) - \(\dfrac{5}{25}\))
= -\(\dfrac{4}{5}\) : \(\dfrac{11}{25}\)
= - \(\dfrac{4}{5}\) x \(\dfrac{25}{11}\)
= - \(\dfrac{20}{11}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
10 tháng 7 2024
\(\dfrac{4}{5}\): (\(\dfrac{4}{5}\).-\(\dfrac{5}{4}\)) : (\(\dfrac{16}{25}\) - \(\dfrac{1}{5}\))
=\(\dfrac{4}{5}\) x - 1: (\(\dfrac{16}{25}\) - \(\dfrac{5}{25}\))
= - \(\dfrac{4}{5}\) : \(\dfrac{11}{25}\)
= - \(\dfrac{4}{5}\) x \(\dfrac{25}{11}\)
= - \(\dfrac{20}{11}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
10 tháng 7 2024
\(\dfrac{11}{12}\): (\(\dfrac{7}{9}\) + - \(\dfrac{1}{3}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{5}{15}\))
= \(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) - \(\dfrac{3}{9}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{11}{12}\) : \(\dfrac{4}{9}\) - \(\dfrac{1}{3}\)
= \(\dfrac{11}{12}\) x \(\dfrac{9}{4}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{16}{48}\)
= \(\dfrac{83}{48}\)
CM
29 tháng 6 2019
Phương pháp giải:
Nhẩm lại bảng nhân và chia trong phạm vi đã học rồi điền kết quả vào chỗ trống.
Lời giải chi tiết:
| 4 × 5=20 | 5 × 4=20 | 20 : 4=5 | 20 : 5=4 |
| 3 × 4=12 | 4 × 3=12 | 12 : 3=4 | 12 : 4=3 |
| 4 × 2=8 | 2 × 4=8 | 8 : 4=2 | 8 : 2=4 |
| 2 × 3=6 | 3 × 2=6 | 6 : 2=3 | 6 : 3=2 |
14 tháng 4 2017
\(-1\dfrac{1}{5}.\dfrac{12+\dfrac{4}{3}-\dfrac{12}{37}-\dfrac{12}{35}}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}}:\dfrac{4+\dfrac{4}{17}+\dfrac{4}{19}+\dfrac{4}{2003}}{5+\dfrac{5}{17}+\dfrac{5}{19}+\dfrac{5}{2003}}\)
\(=\dfrac{-6}{5}.\dfrac{4\left(3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}\right)}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}}:\dfrac{4\left(1+\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{2003}\right)}{5\left(1+\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{2003}\right)}\)
\(=\dfrac{-6}{5}.4:\dfrac{4}{5}\)
\(=\dfrac{-6.4.5}{5.4}=-6\)
HN
1
\(\dfrac{-5}{3}-\left(\dfrac{5}{12}-\dfrac{3}{4}\right)< x< \dfrac{11}{6}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)\)
\(\Rightarrow\left\{{}\begin{matrix}x>\dfrac{-5}{3}-\left(\dfrac{5}{12}-\dfrac{3}{4}\right)\\x< \dfrac{11}{6}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>\dfrac{-5}{3}-\dfrac{5}{12}+\dfrac{3}{4}\\x< \dfrac{11}{6}-\dfrac{1}{3}-\dfrac{1}{4}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>\dfrac{-20}{12}-\dfrac{5}{12}+\dfrac{9}{12}\\x< \dfrac{22}{12}-\dfrac{4}{12}-\dfrac{3}{12}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>-\dfrac{4}{3}\\x< \dfrac{5}{4}\end{matrix}\right.\Rightarrow x\in\left\{-\dfrac{4}{3};\dfrac{5}{4}\right\}}\)
bạn viết gì mk chả hiểu gì cả