Phân tích các đa thức sau thành nhân tử
(5x-4)2-49x2
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Ta có : x2 + 5x + 4
= x2 + x + 4x + 4
= x(x + 1) + 4(x + 1)
= (x + 1)(x + 4)
\(x^4-5x^2+4=x^4-x^2-4x^2+4=x^2\left(x^2-1\right)-4\left(x^2-1\right)=\left(x^2-4\right)\left(x^2-1\right)\)
\(=\left(x-2\right)\left(x+2\right)\left(x-1\right)\left(x+1\right)=\left(x-2\right)\left(x-1\right)\left(x+1\right)\left(x+2\right)\)
Ta có : x4 - 5x2 + 4
= x4 - x2 - 4x2 + 4
= x2(x2 - 1) + (4x2 - 4)
= x2(x2 - 1) + 4(x2 - 1)
= (x2 - 1)(x2 + 4)
\(3x\left(x-2\right)-x+2+5x\left(x-2\right)=\left(x-2\right)\left(8x-1\right)\)
\(3x\left(x-2\right)-x+2+5x\left(x-2\right)=3x\left(x-2\right)-\left(x-2\right)+5x\left(x-2\right)=\left(x-2\right)\left(3x=1+5x\right)=\left(x-2\right)\left(8x-1\right)\)
x2 + 5x + 4
= x2 + x + 4x + 4
(Tách 5x = x + 4x)
= x(x + 1) + 4(x + 1)
(có x + 1 là nhân tử chung)
= (x + 1)(x + 4)
\(5x^2-19x-4\)
\(=\left(5x^2-20x\right)+\left(x-4\right)\)
\(=5x\left(x-4\right)+\left(x-4\right)\)
\(=\left(x-4\right)\left(5x+1\right)\)
\(5x^2-19x-4=5x^2+x-20x-4\)
\(=x\cdot\left(5x+1\right)-4\cdot\left(5x+1\right)\)
\(=\left(5x+1\right)\cdot\left(x-4\right)\)
x 3 – 5 x + 4 = x 3 – x – 4 x + 4 = x ( x 2 – 1 ) – 4 ( x – 1 )
= x(x – 1)(x + 1) – 4(x – 1)
= (x – 1)[x(x + 1) – 4]
= (x – 1)( x 2 + x – 4)
Đáp án cần chọn là: C
\(\left(5x-4\right)^2-49x^2\)
\(=\left(5x-4\right)^2-\left(7x\right)^2\)
\(=\left(5x-4-7x\right)\left(5x-4+7x\right)\)
\(=\left(-2x-4\right)\left(12x-4\right)\)
Chúc bạn học tốt!!!
\(\left(5x-4\right)^2-49x^2\)
= \(\left(5x-4\right)^2-(7x)^2\)
= \(\left(5x-4-7x\right)\left(5x-4+7x\right)\)
= \(\left(-2x-4\right)\left(12x-4\right)\)
= \([2\left(-x-2\right)].[4\left(3x-1\right)]\)
= \(8\left(-x-2\right)\left(3x-1\right)\)