Tìm x biết x- (17 + x ) = x - 19
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\(\left(\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+\frac{2}{17\times19}+\frac{2}{19\times21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)
\(\frac{10}{231}\times462-x=19\)
\(20-x=19\)
\(\Rightarrow x=20-19=1\)
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a/ -x + 8 = -17-30
-x + 8 = -47
-x = -47 - 8
-x = -55
x = 55
Vậy x = 55
b/ 35 – x = 37
x = 35 - 37
x = -2
Vậy x = -2
c/ (-19 – x) + 23 = -20
-19 – x = -20 - 23
-19 – x = -43
x = -19 - (-43)
x = 24
Vậy x = 24
d/ (x – 45) : 2 = -17
x – 45 = -17 * 2
x – 45 = -34
x = -34 + 45
x = 11
Vậy x = 11
a/ -x + 8 = -17-30
-x + 8 = -47
-x =-47 - 8
-x = -55
x = 55
Vậy x = 55
Phần a mình bị lỗi nên sửa lại nha
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16< x < 19
vì 16 < 17 < 18 < 19
vậy x = 17; 18
vì x là số chẵn vậy x = 18
Chọn C. 18
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\(\dfrac{x}{17}+\dfrac{19}{34}=2\dfrac{1}{2}\)
\(\Rightarrow\dfrac{x}{17}+\dfrac{19}{24}=\dfrac{5}{2}\)
\(\Rightarrow\dfrac{x}{17}=\dfrac{33}{17}\Rightarrow x=33\)
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\(a,-x+8=-17\)
<=>\(-x=\left(-17\right)-8\)
<=>\(-x=-25\)
<=>\(x=25\)
\(b,35-x=37\)
<=>\(x=35-37\)
<=>\(x=-2\)
\(c,-19-x=-20\)
<=>\(x=\left(-19\right)+20\)
<=>\(x=1\)
\(d,x-45=-17\)
<=>\(x=\left(-17\right)+45\)
<=>\(x=28\)
1.
a,-x+8=-17
-x=-17-8=-25
-x=-25
x=25
b,35-x=37
x=35-37
x=-2
c,-19-x=-20
x=-19--20
x=1
d,x-45=-17
x =-17+-45
x=-62
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a) -x +8=-17-30
-x+8+17+30=0
-x+55=0
-x=-55
x=55
b) 35-x=37
x=-2
c)(-19-x)+23=-20
-19-x+23+20=0
24-x=0
x=24
d) ( x-45):2=-17
x-45=-34
x=11
a) -x + 8 = -17 - 30
-x + 8 = -47
-x = -47 - 8
-x = -55
=> x = 55
Vậy x = 55
b) 35 - x = 37
x = 35 - 37
x = -2
Vậy x = -2
c)( -19 - x) + 23 = -20
(-19 - x) = -20 - 23
-19 - x = -43
x = -19 - (-43)
x = 24
Vậy x - 24
d)(x - 45) : 2 = -17
x - 45 = -17 . 2
x - 45 = -34
x = -34 + 45
x = 11
Vậy x = 11