10 + 2 . x = 45 : 43
720 : [ 41 - ( 2.x - 5 )] = 23 . 5
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b, 92 : 4 - 27 = \(\dfrac{x+350}{x}\) + 315
23 - 27 = 1 + \(\dfrac{350}{x}\) + 315
316 + \(\dfrac{350}{x}\) = -4
\(\dfrac{350}{x}\) = - 316 - 4
\(\dfrac{350}{x}\) = -320
-320 \(x\) = 350
\(x\) = 350: (-320)
\(x\) = - \(\dfrac{35}{32}\) (loại)
Vậy \(x\) \(\in\) \(\varnothing\)
c, 720 : [ 41 - (2\(x\) - 5)] = 23.5
41 - (2\(x\) - 5) = 720 : (23.5)
41 - 2\(x\) + 5 = 18
46 - 2\(x\) =18
2\(x\) = 46 - 18
2\(x\) = 28
\(x\) = 28: 2
\(x\) = 14
Vậy \(x\) = 14
a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)
=>\(\left[2\left(10-x\right)+51\right]:3=5\)
=>\(\left[2\left(10-x\right)+51\right]=15\)
=>\(2\left(10-x\right)=15-51=-36\)
=>10-x=-36/2=-18
=>\(x=10-\left(-18\right)=10+18=28\)
b: \(\left(x-12\right)-15=20-\left(17+x\right)\)
=>\(x-12-15=20-17-x\)
=>\(x-27=3-x\)
=>\(2x=30\)
=>\(x=\dfrac{30}{2}=15\)
c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
=>\(720-\left[41-2x+5\right]=8\cdot5=40\)
=>\(\left[41-2x+5\right]=720-40=680\)
=>-2x+46=680
=>-2x=680-46=634
=>\(x=\dfrac{634}{-2}=-317\)
\(a,x-36:18=12-15\\ \Rightarrow x-2=-3\\ \Rightarrow x=-1\\ b,92-\left(17+x\right)=72\\ \Rightarrow17+x=20\\ \Rightarrow x=3\\ c,720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=18\\ \Rightarrow x=9\\ d,\left(x+2\right)^3-23=41\\ \Rightarrow\left(x+2\right)^3=64\\ \Rightarrow\left(x+2\right)^3=4^3\\ \Rightarrow x+2=4\\ \Rightarrow x=2\)
280 - ( x - 140 ) : 35 = 270
<=> ( x - 140 ) : 35 = 280 -270
<=> ( x -140 ) : 35 = 10
<=> x -140 = 10 . 35
<=> x -140 = 350
<=> x = 350 + 140
<=> x = 490
1) 280 - ( x - 140 ) : 35 = 270
=> ( x - 140 ) : 35 = 280 - 270 = 10
x - 140 = 350
=> x = 350 + 140
=> x = 390
2) ( 190 - 2x ) : 35 - 32 = 16
190 - 2x = ( 16 + 32 ) . 35 = 1680
x = ( 190 - 1680 ) : 2
x = -745
3) 720 : { 41 - ( 2x - 5 )} -2.5
Sai đề.
4) ( x : 23 + 45 ) . 37 - 22 = 24 .105
x : 23 + 45 = ( 24.105 + 22 ) : 37
x : 23 = 2542/37 - 45 = 877/37
x = 877/37.23 = 20171/37
5) ( 3x - 4 ) ( x - 1 ) = 0
=> 3x - 4 = 0 hoặc x - 1 = 0
3x - 4 = 0 hoặc x - 1 = 0
=> x = 4/3 => x = 1
Vậy x \(\in\) { 4/3;1 }
6) 22x : 4 = 83
=> 22x = 83 . 4 = 2048 = 211
=> 2x = 11
=> x = 11/2
a, 70 - 5 ( x - 3 ) = 45
⇔ 5 . x - 3 = 70 - 45
⇔ 5 x - 3 = 35
⇔ x - 3 = 35 : 5 ⇔ x - 3 = 7
⇔ x = 10
b, 10 + 2 x = 4 5 : 4 3
⇔ 10 + 2 x = 4 2 ⇔ 10 + 2 x = 16
⇔ 2 x = 4 ⇔ x = 2
c, 60 - 3 x - 2 = 51
⇔ 3 x - 2 = 60 - 51
⇔ 3 x - 2 = 9
⇔ x - 2 = 3 ⇔ x = 5
d, 4 x - 20 = 2 5 : 2 3
⇔ 4 x - 20 = 2 2 ⇔ 4 x - 20 = 4
⇔ 4 x = 24 ⇔ x = 6
a, \(x-105:21=15\)
\(x-5=15\)
\(x=20\)
b, \(\left(x-105\right):21=15\)
\(x-105=315\)
\(x=315+105=420\)
c, \(\left(x:23+45\right).67=8911\)
\(x:23+45=133\)
\(x:23=88\)
\(x=88.23=2024\)
d, \(720:\left[41-\left(2x-5\right)\right]=8.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=18\)
\(2x-5=23\)
\(2x=28\)
\(x=14\)
Chúc bạn học tốt
Bài 5: Tìm x thuộc số tự nhiên:
a) x - 105 : 21= 15
x - 5 = 15
x = 15 + 5
x = 20
b) (x - 105) : 21 = 15
x - 105 = 15 . 21
x - 105 = 315
x = 315 + 105
x = 420
c) ( x : 23 + 45) . 67 = 8911
x : 23 + 45 = 8911 : 67
x : 23 + 45 = 133
x : 23 = 133 - 45
x : 23 = 88
x = 88 . 23
x = 2024.
d) 720: [41 - (2 . x - 5)] = 8 . 5
720: [41 - (2 . x - 5)] = 40
41 - (2 . x - 5) = 720 : 40
41 - (2 . x - 5) = 18
2 . x - 5 = 41 - 18
2 . x - 5 = 23
2 . x = 23 + 5
2 . x = 28
x = 28 : 2
x = 19
10 + 2 . x = 45 : 43
10+2x=42
2x=16-10
2x=6
x=6:2
x=3
720 : [ 41 - ( 2.x - 5 )] =23 . 5
720 : [ 41 - ( 2.x - 5 )] =40
41 - ( 2.x - 5 ) = 720:40
41 - ( 2.x - 5 ) = 18
2.x - 5=23
2x=23+5
2x=28
x=28:2
x=14
10 + 2 . x = 45 : 43
10 + 2 . x = 45-3
10 + 2 . x = 42
10 + 2 . x = 16
2 . x = 16-10
2 . x = 6
x=6:2
x=3
720 : [ 41 - ( 2.x - 5 )] = 23 . 5
720 : [ 41 - ( 2.x - 5 )] =8 . 5
720 : [ 41 - ( 2.x - 5 )] =40
41 - ( 2.x - 5 )=720 : 40
41 - ( 2.x - 5 )=18
2.x - 5=41-18
2.x - 5=23
2.x=23+5
2.x=28
x=28:2
x=14