2^15.9^4/6^8.8^3
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tìm giá trị của biểu thức sau
a) 45 mũ 10 . 5 mũ 20 / 75 mũ 15
b) (0,8) mũ 5 / (0,4) mũ 6
c) 2 mũ 15 . 9 mũ 4 / 6 mũ 6 . 8 mũ 3
bài làm là:
a) 45^10.5^20/75 ^ 15
=(5.9)^10.5^20/(5.15)^15
=5^10.9^10.5^20/5^15.15^15
=5^30.3^20/5^15.3^15.5^15
=5^30.3^20/5^30.3^15
=5^30.3^20/5^30.3^15
=3^5
=243
mấy ý kia mình chia tính được ....A,hihi
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A= (910.510.510)/(2510.310)=(320.520)/(520.310)=310
B=(0,8)5/(0,4)6= (2.0,4)5/0,4.0,45 = 25.0,45/0,4.0,45 = 25/0,4 = 80
C= 215.94/66.83= 215.38/36.26.29=215.38/36.215=32=9
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\(\dfrac{2^{15}\cdot9^4}{6^8\cdot8^3}=\dfrac{2^{15}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^8\cdot\left(2^3\right)^3}=\dfrac{2^{15}\cdot3^8}{2^8\cdot3^8\cdot2^9}=\dfrac{2^{15}\cdot3^8}{2^{17}\cdot3^8}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
\(\dfrac{2^{15}.9^4}{6^8.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^8.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^8.3^8.2^9}=\dfrac{2^{15}}{2^{17}}=\dfrac{1}{2^2}=\dfrac{1}{4}\)
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\(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}\)
\(=\frac{\left(2.3\right)^{15}.3^{20}}{3^{34}.2^{13}}\)
\(=\frac{2^{15}.3^{25}}{3^{34}.2^{13}}\)
\(=\frac{2^2.3}{1.1}=2^2.3=12\)
\(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}=\frac{2^{15}.3^{15}.3^{20}}{3^{34}.2^{13}}=\frac{2^{15}.3^{35}}{3^{34}.2^{13}}=2^2.3=12\)
2^15 . 9^4/6^8 . 8^3
2^15 . (3^2)^4 / 2^8.3^8 . (2^3)^3
2^15. 3^8 / 2^8 . 3^8 . 2^9
2^15 . 3^8 / 2^15 . 3^8
suy ra : (2^15 . 3^8) :( 2^15 . 3^8) = 1