Đưa thừa số ra ngoài dấu căn: \(\sqrt{48y^8}\)
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\(\sqrt{50.6}=\sqrt{300}=\sqrt{2^2.5^2.3}=2.5\sqrt{3}=10\sqrt{3}\)
a/ \(\sqrt{50a}=5\sqrt{2a}\)
b/ \(\sqrt{75x}=5\sqrt{3x}\)
\(\sqrt{18b^3\cdot\left(1-2a\right)^2}\)
\(=3\sqrt{2}\cdot b\sqrt{b}\cdot\left|1-2a\right|\)
\(=3\sqrt{2}\left(2a-1\right)\cdot b\sqrt{b}\)
\(\sqrt{34+24\sqrt{2}}=\sqrt{18+2.3\sqrt{2}.4+16}\)
\(=\sqrt{\left(3\sqrt{2}+4\right)^2}=3\sqrt{2}+4\)
\(\sqrt{48\cdot45}=12\sqrt{15}\\ \sqrt{225\cdot17}=15\sqrt{17}\\ \sqrt{a^3b^7}=\left|ab^3\right|\sqrt{ab}=ab^3\sqrt{ab}\\ \sqrt{x^5\left(x-3\right)^2}=\left|x^2\left(x-3\right)\right|\sqrt{x}=x^2\left(x-3\right)\sqrt{x}\)
\(\sqrt{48\cdot45}=4\sqrt{3}\cdot3\sqrt{5}=12\sqrt{15}\)
\(\sqrt{225\cdot17}=15\sqrt{17}\)
\(\sqrt{\dfrac{45\left(x+y\right)^2.y^2}{16}}\left(dkxd:x\ge0,y\ge0\right)\\ =\dfrac{\sqrt{45\left(x+y\right)^2.y^2}}{\sqrt{16}}\\ =\dfrac{\sqrt{45}.\sqrt{\left(x+y\right)^2}.\sqrt{y^2}}{\sqrt{4^2}}\\ =\dfrac{\sqrt{3^2.5}.\left|x+y\right|.\left|y\right|}{4}\\ =\dfrac{3\sqrt{5}\left(x+y\right).y}{4}\\ =\dfrac{3\sqrt{5}\left(xy+y^2\right)}{4}\)
\(\sqrt{x^3-6x^2+12x-8}\)
\(=\sqrt{\left(x-2\right)^3}\)
\(=\left|x-2\right|\cdot\sqrt{x-2}\)
\(\sqrt{48y^8}=\sqrt{48}.\sqrt{y^8}=4\sqrt{3}y^4\)
\(\sqrt{48y^8}=\sqrt{16\cdot3\cdot y^8}=\left|16\right|\cdot\left|y^4\right|\cdot\sqrt{3}=4\sqrt{3}y^4\)