12^18 va 27^16*16^9
giup minh voi
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\(\left\{{}\begin{matrix}26⋮x\\x\ge13\end{matrix}\right.\Rightarrow x\in\left\{13;26\right\}\)
\(\left\{{}\begin{matrix}16⋮x\\x< 8\end{matrix}\right.\Rightarrow x\in\left\{1;2;4\right\}\)
\(\left\{{}\begin{matrix}18⋮x\\0< x< 40\end{matrix}\right.\Rightarrow x\in\left\{1;2;3;6;9;18\right\}\)
\(\left\{{}\begin{matrix}x⋮15\\30< x< 40\end{matrix}\right.\Rightarrow x\in\varnothing\)
\(\left\{{}\begin{matrix}x⋮12\\22\le5x\le50\end{matrix}\right.\Rightarrow x\in\varnothing\)
\(\left\{{}\begin{matrix}x⋮4\\16\le x\le36\end{matrix}\right.\Rightarrow x\in\left\{16;20;24;28;32;36\right\}\)
Ta có:
12^8=(3.2^2)^8=3^8.2^16
27^16.16^9=(3^3)^16.(2^4)^9=3^48.2^36
<=>12^8<27^16.16^9
a: \(\left(-\dfrac{1}{16}\right)^{100}=\left(\dfrac{1}{16}\right)^{100}=\left(-\dfrac{1}{2}\right)^{400}\)
\(\left(-\dfrac{1}{2}\right)^{500}=\left(-\dfrac{1}{2}\right)^{500}\)
mà \(400< 500\)
nên \(\left(-\dfrac{1}{16}\right)^{100}< \left(-\dfrac{1}{2}\right)^{500}\)
x+27=26-14 x+27= 12 x=12-27 x=-15 x-16=79+12 x-16=91 x= 91+16 x=107
\(\dfrac{5}{15}+\dfrac{3}{12}+\dfrac{2}{10}+\dfrac{18}{27}+\dfrac{12}{16}+\dfrac{20}{25}\)
\(=\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{1}{4}+\dfrac{3}{4}+\dfrac{1}{5}+\dfrac{4}{5}\)
=3
\(\dfrac{3}{4}-\dfrac{3}{12}=\dfrac{3\times3}{4\times3}-\dfrac{3}{12}=\dfrac{9}{12}-\dfrac{3}{12}=\dfrac{9-3}{12}=\dfrac{6}{12}=\dfrac{1}{2}\\ \dfrac{16}{9}-\dfrac{18}{27}=\dfrac{16}{9}-\dfrac{2}{3}=\dfrac{16}{9}-\dfrac{2\times3}{3\times3}=\dfrac{16}{9}-\dfrac{6}{9}=\dfrac{16-6}{9}=\dfrac{10}{9}\)
9/12 - 3/12 = 3/12
48/27 - 18/27 = 30/27
Học tốt nha. Nhớ tick cho tui nha