\(x\div3=10\div15\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left[\left(10-x\right).2+5\right]\div3-x=3\)
\(\Rightarrow\left[20-2x+5\right]\div3-x=3\)
\(\Rightarrow25-2x=\left(3+x\right).3\)
\(\Rightarrow25-2x=9+3x\)
\(\Rightarrow25=9+5x\)
\(\Rightarrow5x=16\)
\(\Rightarrow x=3,2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
[(10-x).2+5]:3-2=3
[(10-x).2+5]:3=3+2
[(10-x).2+5]:3=5
[(10-x).2+5]=5.3
(10-x).2+5=15
(10-x).2=15-5
(10-x).2=10
10-x=10:2
10-x=5
x=10-5
x=5
\(\left[\left(10-x\right).2+5\right]:3-2=3\)
\(\Rightarrow\left(10-x\right).2+5=\left(3+2\right).3\)
\(\Rightarrow\left(10-x\right).2+5=15\)
\(\Rightarrow10-x=\left(15-5\right):2\)
\(\Rightarrow10-x=5\)
\(\Rightarrow x=10-5\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
khỏi chép lại đề nha
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right):15=0+\frac{3}{4}\)
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right):15=\frac{3}{4}\)
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right)=\frac{3}{4}.15\)
\(1-\left(\frac{49}{9}+x-\frac{133}{18}\right)=\frac{45}{4}\)
\(\frac{49}{9}+x-\frac{133}{18}=1-\frac{45}{4}\)
\(\frac{49}{9}+x-\frac{133}{18}=\frac{-41}{4}\)
\(\frac{49}{9}+x=\frac{-41}{4}+\frac{133}{18}\)
\(\frac{49}{9}+x=\frac{-103}{36}\)
\(x=\frac{-103}{3}-\frac{49}{9}\)
\(x=\frac{-299}{36}\)
tk mik nha
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\left(-\dfrac{5}{8}\right)-x:3\dfrac{5}{6}+7\dfrac{3}{4}=-2\)
\(\Leftrightarrow\dfrac{-5}{8}-x:\dfrac{23}{6}+\dfrac{31}{4}+2=0\)
\(\Leftrightarrow x:\dfrac{-23}{6}+\dfrac{73}{8}=0\)
\(\Leftrightarrow x\cdot\dfrac{-6}{23}=-\dfrac{73}{8}\)
\(\Leftrightarrow x=-\dfrac{73}{8}:\dfrac{-6}{23}=\dfrac{-73}{8}\cdot\dfrac{23}{-6}\)
hay \(x=\dfrac{1679}{48}\)
Vậy: \(x=\dfrac{1679}{48}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(60\%x+0,4x+x:3=2\)
\(\Leftrightarrow\frac{3}{5}x+\frac{2}{5}x+\frac{1}{3}x=2\)
\(x\left(\frac{3}{5}+\frac{2}{5}+\frac{1}{4}\right)=2\)
\(x.\frac{4}{3}=2\)
\(x=2:\frac{4}{3}\)
\(x=\frac{3}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x}{3}=\frac{10}{15}\Rightarrow x=\frac{10.3}{15}=2\)