64 x 6x=168
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a. 168x168-168x68
= 168x(168-68)
= 168x100
= 16800
b. 201,5x17-2015x16-201,5
= 201,5x17-201,5x160-201,5
= 201,5x(17-16-1)
= 201,5x0
= 0
c. 1,5 + 1,5x2+1,5x7-10
= 1,5x1+1,5x2+1,5x7-10
= 1,5x(1+2+7)-10
= 1,5x10-10
= 10x(1,5-1)
= 10x0,5
= 5
d. 1,25x2,5x64
= 1,25x64x2,5
=80x2,5
= 200
a)168*168-168*68=168*(168-68)=168*100=16 800
b)201,5*17-2015*16-201,5=201,5*17-201,5*160-201,5=201,5*(17-160-1)=201,5*(-144)=-29016
c)1,5+1,5*2+1,5*7-10=1,5*(1+2+7)-10=1,5*10-10=(1,5-1)*10=0,5*10=5
d)1,25*2,5*64=1,25*2,5*8*8=(1,25*8)*(2,5*8)=10*20=200


Đặt \(A=\sqrt{x^2-6x+36}+\sqrt{x^2-6x+64}=18\)
\(B=\sqrt{x^2-6x+64}-\sqrt{x^2-6x+36}\)
\(\Rightarrow A.B=\left(x^2-6x+64\right)-\left(x^2-6x+36\right)=28\)
mà \(A=18\Rightarrow B=\frac{28}{18}=\frac{14}{9}\)

`64.4^x=168`
`<=>4^x=168/64=21/8`
Vì `x\inNN` nên không tồn tại `x`
Kết luận:.....

\(64\cdot4^x=16^8\\ \Rightarrow4^3\cdot4^x=\left(4^2\right)^8\\ \Rightarrow4^3\cdot4^x=4^{16}\\ \Rightarrow4^x=4^{16}:4^3\\ \Rightarrow4^x=4^{13}\\ \Rightarrow x=13\)
Vậy `x=13`
64.4x=168
4x=168:64
4x=(42)8:43
4x=416:43
4x=416-3
4x=413
x=13
Vậy x=13

Bài 4:
a, \(x^3+12x^2+48x+64=x^3+4x^2+8x^2+32x+16x+64\)
\(=x^2.\left(x+4\right)+8x.\left(x+4\right)+16.\left(x+4\right)\)
\(=\left(x+4\right).\left(x^2+8x+16\right)=\left(x+4\right).\left(x^2+4x+4x+16\right)\)
\(=\left(x+4\right).\left(x+4\right)^2=\left(x+4\right)^3\)(1)
Thay \(x=6\) vào (1) ta được:
\(\left(6+4\right)^3=10^3=1000\)
Vậy...........
b, \(x^3-6x^2+12x-8=x^3-2x^2-4x^2+8x+4x-8\)
\(=x^2.\left(x-2\right)-4x.\left(x-2\right)+4.\left(x-2\right)\)
\(=\left(x-2\right).\left(x^2-4x+4\right)=\left(x-2\right).\left(x^2-2x-2x+4\right)\)
\(=\left(x-2\right).\left(x-2\right)^2=\left(x-2\right)^3\)(2)
Thay \(x=22\) vào (2) ta được:
\(\left(22-2\right)^3=20^3=8000\)
Vậy.............
Chúc bạn học tốt!!!
Bài 2:
a, \(\left(x+9\right)^3=27=3^3\)
\(\Rightarrow x+9=3\Rightarrow x=-6\)
Vậy.........
b, \(8-12x-x^3+6x^2=-64\)
\(\Rightarrow-\left(x^3-6x^2+12x-8\right)=-64\)
\(\Rightarrow x^3-2x^2-4x^2+8x+4x-8=64\)
\(\Rightarrow x^2.\left(x-2\right)-4x.\left(x-2\right)+4.\left(x-2\right)=64\)
\(\Rightarrow\left(x-2\right).\left(x^2-4x+4\right)=64\)
\(\Rightarrow\left(x-2\right).\left(x^2-2x-2x+4\right)=64\)
\(\Rightarrow\left(x-2\right).\left(x-2\right)^2=64\)
\(\Rightarrow\left(x-2\right)^3=4^3\Rightarrow x-2=4\Rightarrow x=6\)
Vậy............
Chúc bạn học tốt!!!

\(\left(\frac{1}{2}-\frac{1}{3}\right).6x+6x+2=67+64\)
\(\frac{\Rightarrow1}{6}.6x+6x+2=131\)
\(\Rightarrow x+6x=131-2\)
\(\Rightarrow7x=129\)
\(\Rightarrow x=\frac{129}{7}\)


[(6x² - 12) : 3] . 16 = 64
(6x² - 12) : 3 = 64 : 16
(6x² - 12) : 3 = 4
6x² - 12 = 4 . 3
6x² - 12 = 12
6x² = 12 + 12
6x² = 24
x² = 24 : 6
x² = 4
x = 2 hoặc x = -2
\(\left[\left(6x^2-12\right):3\right]\times16=64\\ \left(6x^2-12\right):3=4\\ 6x^2-12=12\\ 6x^2=24\\ x^2=4\\ x^2=2^2\\ x=2.\)