làm hộ mik 91,92 k
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#include <bits/stdc++.h>
using namespace std;
double a,b,c,p,s;
int main()
{
cin>>a>>b>>c;
p=(a+b+c)/2;
s=sqrt(p*(p-a)*(p-b)*(p-c));
cout<<fixed<<setprecision(2)<<p;
return 0;
}
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1:
uses crt;
var a,b,c,max,min:longint;
begin
clrscr;
readln(a,b,c);
max=a;
if max<b then max:=b;
if max<c then max:=c;
min:=a;
if min>c then min:=c;
if min>b then min:=b;
writeln(max,' ',min);
readln;
end.
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(100-90):1+1=11(số) dãy số có 11 số
tổng các số hang là
(100+90)x11:2=1045
đáp số 1045
có saithi cho minh xin loi
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Bài 91:
a) \(2^6\) = 2.2.2.2.2.2 = 64; \(8^2\) = 8.8 = 64
Vậy \(2^6\)=\(8^2\)
b) \(5^3\) = 5.5.5 = 125; \(3^5\) = 3.3.3.3.3 = 243
Vậy \(5^3\)<\(3^5\)
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Bài 1:
\(a)\left(x+\dfrac{2}{3}\right)^3=\dfrac{125}{64}.\\ \Leftrightarrow\left(x+\dfrac{2}{3}\right)^3=\left(\dfrac{5}{4}\right)^3.\\ \Rightarrow x+\dfrac{2}{3}=\dfrac{5}{4}.\\ \Leftrightarrow x=\dfrac{7}{12}.\)
\(b)\left(x-\dfrac{1}{2}\right)^3=\dfrac{8}{343}.\\\Leftrightarrow\left(x-\dfrac{1}{2}\right)^3=\left(\dfrac{2}{7}\right) ^3.\\ \Rightarrow x-\dfrac{1}{2}=\dfrac{2}{7}.\\ \Leftrightarrow x=\dfrac{11}{14}.\)
Bài 2:
\(a)\left(x-\dfrac{1}{3}\right)^2=\dfrac{25}{9}.\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-\dfrac{1}{3}\right)^2=\left(\dfrac{5}{3}\right)^2.\\\left(x-\dfrac{1}{3}\right)^2=\left(\dfrac{-5}{3}\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{5}{3}.\\x-\dfrac{1}{3}=\dfrac{-5}{3}.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2.\\x=\dfrac{-4}{3}.\end{matrix}\right.\)
\(b)\left(x-\dfrac{3}{4}\right)^2=\dfrac{49}{16}.\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-\dfrac{3}{4}\right)^2=\left(\dfrac{7}{4}\right)^2.\\\left(x-\dfrac{3}{4}\right)^2=\left(\dfrac{-7}{4}\right)^2.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{7}{4}.\\x-\dfrac{3}{4}=\dfrac{-7}{4}.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}.\\x=-1.\end{matrix}\right.\)
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Trả lời:
91, 8a3 + 12a2 + 6a + 1
= ( 2a )3 + 3.(2a)2.1 + 3.2a.1 + 13
= ( 2a + 1 )3
92, 8a3 - 12a2 + 6a - 1
= ( 2a )3 - 3.(2a)2 + 3.2a.1 - 13
= ( 2a - 1 )3
8a3-12a2+6a-1
=8a^3-4a^2-8a^2+4a+2a-1
=4a^2(2a-1)-4a(2a-1)+2a-1
=(2a-1)(4a^2-4a-1)